To find the ratio of the maximum power delivered by circuit A to that delivered by circuit B, we use the formula for electric power:

$P = V \times I$

Where:

• $P$ is the power in watts,
• $V$ is the voltage in volts,
• $I$ is the current in amperes.

For Circuit A:

$P_A = 188 \, \text{V} \times 45 \, \text{A} = 8460 \, \text{W}$

For Circuit B:

$P_B = 120.0 \, \text{V} \times 21 \, \text{A} = 2520 \, \text{W}$

Now, to find the ratio of the maximum power delivered by Circuit A to that delivered by Circuit B: $\text{Ratio} = \frac{P_A}{P_B} = \frac{8460 \, \text{W}}{2520 \, \text{W}} = 3.36$

Thus, the ratio of the maximum power delivered by Circuit A to that delivered by Circuit B is 3.36.

Would you like more details on power calculations or have any questions?

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Here are 5 follow-up questions for further exploration:

1. What would happen if the voltage in Circuit B was increased?
2. How would the ratio change if the current in Circuit A was reduced to 30 A?
3. What is the effect of increasing voltage on power consumption in general?
4. How do circuit breakers protect electrical systems from overload?
5. Can you calculate energy consumption for a given device over time using these values?

Tip: Always ensure that the power rating of appliances is below the maximum power capacity of the circuit to prevent tripping the breaker.