Math Problem Statement

A 1.5-V battery is connected to a circuit and puts out a current of 0.45 A. How much power is the battery putting out?

Solution

To solve this problem, we can use the formula for electric power:

P=V×IP = V \times I

Where:

  • PP is the power (in watts),
  • VV is the voltage (in volts),
  • II is the current (in amperes).

Given:

  • V=1.5VV = 1.5 \, \text{V},
  • I=0.45AI = 0.45 \, \text{A}.

Substituting these values into the formula:

P=1.5×0.45=0.675WP = 1.5 \times 0.45 = 0.675 \, \text{W}

Thus, the power output is approximately 0.68W\mathbf{0.68 \, W}.

Would you like more details or have any questions?

Here are some related questions for further practice:

  1. How would the power change if the current was increased to 0.9 A?
  2. What happens to the power if the voltage was doubled but the current remained constant?
  3. Can you calculate the resistance of the circuit using Ohm's Law?
  4. How much energy is delivered if the battery operates for 2 hours?
  5. What type of circuit could lead to higher power consumption for the same voltage?

Tip: Remember that power in an electric circuit depends on both the voltage and the current, and any change in either can significantly affect the power output.

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Math Problem Analysis

Mathematical Concepts

Electricity
Power Calculation

Formulas

P = V × I

Theorems

Ohm's Law

Suitable Grade Level

Grades 9-12