Let's define the variables based on the given information:

• Let $T$ represent the total number of employees in the showroom.
• 35% of the employees are female, so the number of female employees is: $F = 0.35T$ This implies the number of male employees is: $M = 0.65T$

Next, we are told that 60% of the male employees are above the age of 30, so the number of male employees above 30 is: $M_{>30} = 0.60 \times 0.65T = 0.39T$

Now, 45% of the total employees are aged either 30 or below. Therefore, the number of employees aged 30 or below is: $E_{\leq30} = 0.45T$ The employees aged 30 or below consist of both males and females. Let $F_{\leq30}$ be the number of female employees aged 30 or below, and $M_{\leq30}$ be the number of male employees aged 30 or below. Then: $F_{\leq30} + M_{\leq30} = 0.45T$ We know that the number of male employees aged 30 or below is: $M_{\leq30} = 0.40 \times 0.65T = 0.26T$ Substituting this into the equation for employees aged 30 or below: $F_{\leq30} + 0.26T = 0.45T$ Solving for $F_{\leq30}$: $F_{\leq30} = 0.45T - 0.26T = 0.19T$

Finally, the problem asks for the ratio of female employees at or below the age of 30 to the male employees above the age of 30. This ratio is: [ \frac{F_{\leq30}}{M_{>30}} = \frac{0.19T}{0.39T} = \frac{19}{39} = \frac{19}{39} = \frac{19}{39} = \frac{19}{39} = \frac{19}{