Math Problem Statement
In triangle ABC, AB = 5 cm, AC = 15 cm and D is a point on BC such that DA bisects . find the ratio of triangle ABC and triangle ACD
Solution
To solve this problem, let's first clarify what is given:
- You have a triangle with cm and cm.
- Point is on side , and bisects the triangle into two parts: and .
You are asked to find the ratio of the areas of and .
Solution
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Understanding the bisector: Since is a bisector, the area of is equal to the area of if were the midpoint of . But in this problem, it is given that bisects .
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Ratio of areas:
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The area of is proportional to the product of the base and the height. If we consider , its base is and its height is the same as because is a bisector.
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The ratio of the areas of two triangles with the same height is equal to the ratio of their bases.
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Use the Side Lengths:
- Let's consider the side lengths and to find the ratio of the areas. Since is a bisector, it divides the opposite side in the ratio of the adjacent sides.
- Thus, the ratio will be equal to .
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Area Ratio:
- The area of is smaller because is smaller than .
- Since the area ratio is given by the square of the corresponding side ratio, the area ratio of to is .
Conclusion
The ratio of the areas of and is .
Would you like details or have any questions?
Here are five related questions:
- What is the significance of the angle bisector theorem in triangle area calculations?
- How do you find the area of a triangle using side lengths?
- What is the relationship between side lengths and area ratios in similar triangles?
- How can you apply the angle bisector theorem in different types of triangles?
- How does the area ratio change if is not on but on an extended line?
Tip: When solving geometry problems, always consider theorems like the angle bisector theorem and properties of triangles to guide you through the solution.
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Math Problem Analysis
Mathematical Concepts
Triangle geometry
Area calculations
Triangle similarity
Formulas
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Theorems
Angle bisector theorem
Suitable Grade Level
High school
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