Math Problem Statement

f(x)= x^2 + 10 can you find the rate of change

Solution

To find the rate of change of the function f(x)=x2+10f(x) = x^2 + 10, we need to calculate its derivative. The derivative represents the rate of change of the function with respect to xx.

Step-by-step:

Given:
f(x)=x2+10f(x) = x^2 + 10

To find the derivative, f(x)f'(x), we apply the power rule:

  1. The derivative of x2x^2 is 2x2x.
  2. The derivative of a constant (in this case, 10) is 0.

So, the derivative is: f(x)=2xf'(x) = 2x

This means the rate of change of the function f(x)f(x) at any point xx is 2x2x.

Conclusion:

The rate of change of f(x)=x2+10f(x) = x^2 + 10 is given by f(x)=2xf'(x) = 2x. At any specific value of xx, you can substitute it into 2x2x to find the exact rate of change at that point.

Would you like to calculate the rate of change at a specific point or explore this further?

Relative questions:

  1. What is the rate of change of f(x)=x2+10f(x) = x^2 + 10 at x=3x = 3?
  2. How do you find the rate of change of a function involving a higher degree polynomial?
  3. What is the difference between average rate of change and instantaneous rate of change?
  4. How does the rate of change vary for f(x)=x2+10f(x) = x^2 + 10 as xx increases?
  5. Can the rate of change of a quadratic function ever be constant?

Tip:

The derivative tells you the instantaneous rate of change at any point. For quadratic functions, the rate of change increases or decreases linearly as xx changes.

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Math Problem Analysis

Mathematical Concepts

Calculus
Rate of Change
Derivatives

Formulas

Derivative of x^2 is 2x
Derivative of a constant is 0

Theorems

Power Rule

Suitable Grade Level

Grades 10-12