Math Problem Statement

Use the given domain to find the range of the following function: f(x) = -2x^2 + 7, D = {2, -3, 0}.

Solution

We are given the function f(x)=2x2+7f(x) = -2x^2 + 7 and the domain D={2,3,0}D = \{2, -3, 0\}. Our goal is to find the range, which means we need to calculate the values of f(x)f(x) for each xx in the domain.

  1. For x=2x = 2: f(2)=2(22)+7=2(4)+7=8+7=1f(2) = -2(2^2) + 7 = -2(4) + 7 = -8 + 7 = -1

  2. For x=3x = -3: f(3)=2((3)2)+7=2(9)+7=18+7=11f(-3) = -2((-3)^2) + 7 = -2(9) + 7 = -18 + 7 = -11

  3. For x=0x = 0: f(0)=2(02)+7=2(0)+7=7f(0) = -2(0^2) + 7 = -2(0) + 7 = 7

Thus, the range RR is the set of the function values: R={1,11,7}R = \{-1, -11, 7\}.

Do you want more details or have any questions?

Here are some related questions:

  1. How does changing the coefficient of x2x^2 affect the range of a quadratic function?
  2. What is the significance of the vertex in determining the range of a quadratic function?
  3. How do you find the domain and range for more complex functions, such as those involving square roots or logarithms?
  4. Can a quadratic function ever have a maximum range value instead of a minimum?
  5. What are the differences between the domain and range in linear versus quadratic functions?

Tip: When working with quadratic functions, the direction of the parabola (opening up or down) is determined by the sign of the coefficient of x2x^2.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions

Formulas

f(x) = ax^2 + bx + c

Theorems

Range of a quadratic function

Suitable Grade Level

Grades 8-10