Math Problem Statement

Natural numbers 1 to 25 (both inclusive) are split into 5 groups of 5 numbers each. The medians of these 5 groups are A, B, C, D and E. If the average of these medians is m, what are the smallest and the largest values m can take?

Solution

To find the smallest and largest values that the average mm of the medians A,B,C,D,EA, B, C, D, E can take, let's break down the problem.

Step 1: Understanding the Problem

  • The natural numbers from 1 to 25 are divided into 5 groups of 5 numbers each.
  • For each group, the median is the middle number when the group is arranged in increasing order.
  • mm is the average of these 5 medians.

Step 2: Properties of the Groups

To minimize or maximize mm, we need to understand how the numbers can be arranged to affect the medians.

  • If the groups are arranged with lower numbers in one group and higher numbers in another, it affects the median values.

Step 3: Minimizing mm

To minimize mm, we want the medians to be as small as possible. This happens when the smallest numbers are grouped together:

  • Group 1: {1,2,3,4,5}\{1, 2, 3, 4, 5\} with median 33
  • Group 2: {6,7,8,9,10}\{6, 7, 8, 9, 10\} with median 88
  • Group 3: {11,12,13,14,15}\{11, 12, 13, 14, 15\} with median 1313
  • Group 4: {16,17,18,19,20}\{16, 17, 18, 19, 20\} with median 1818
  • Group 5: {21,22,23,24,25}\{21, 22, 23, 24, 25\} with median 2323

So, the smallest possible value of mm is: mmin=3+8+13+18+235=655=13m_{\text{min}} = \frac{3 + 8 + 13 + 18 + 23}{5} = \frac{65}{5} = 13

Step 4: Maximizing mm

To maximize mm, we want the medians to be as large as possible. This happens when the highest numbers are grouped together:

  • Group 1: {1,2,23,24,25}\{1, 2, 23, 24, 25\} with median 2323
  • Group 2: {3,4,19,20,22}\{3, 4, 19, 20, 22\} with median 1919
  • Group 3: {5,6,7,8,21}\{5, 6, 7, 8, 21\} with median 77
  • Group 4: {9,10,11,12,18}\{9, 10, 11, 12, 18\} with median 1111
  • Group 5: {13,14,15,16,17}\{13, 14, 15, 16, 17\} with median 1515

So, the largest possible value of mm is: mmax=23+19+7+11+155=755=15m_{\text{max}} = \frac{23 + 19 + 7 + 11 + 15}{5} = \frac{75}{5} = 15

Final Answer:

The smallest value of mm is 13, and the largest value of mm is 15.

Would you like to explore further details or have any questions? Here are some related questions:

  1. How does the median behave under different groupings of data?
  2. What are other ways to arrange groups to get specific median values?
  3. How would this approach change if the range of numbers was different?
  4. Can this method be generalized to more groups or different group sizes?
  5. How do extreme values in data affect the overall median or average?

Tip: In problems involving medians, always consider both extreme and central arrangements to understand the range of possible outcomes.