Here are the computed values of the function:

• $f(-2) = 80$, meaning that 2 seconds before the object was dropped, the object would have been 80 feet above the ground. This doesn't make sense in the context of the problem since negative time isn't meaningful here.
• $f(1.5) = 108$, meaning that 1.5 seconds after the object was dropped, it was 108 feet above the ground. This interpretation makes sense.
• $f(4) = -112$, meaning that 4 seconds after the object was dropped, the object would have been below ground (since the height is negative), which also doesn't make sense physically.

Domain Interpretation:

The domain should exclude negative time and be restricted to non-negative real numbers where the height remains non-negative (i.e., the object is above or on the ground). Therefore, an appropriate domain would be non-negative real numbers up to when the object hits the ground, which happens when $f(x) = 0$.

Let me calculate when the object reaches the ground by solving $f(x) = 0$.The object reaches the ground at $x = 3$ seconds (the solution $x = -3$ is irrelevant since negative time is not physically meaningful).

Conclusion:

The appropriate domain for the function is $0 \leq x \leq 3$, where $x$ represents time in seconds.

Let me know if you'd like further details!

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Here are some follow-up questions:

1. How would the function change if the object were thrown upward instead of dropped?
2. What would the maximum height of the object be?
3. How do we interpret negative values of the function in this context?
4. Could you determine the velocity of the object at any point in time?
5. What real-life factors might affect the accuracy of this model?

Tip: Always check the units and the physical meaning of your results in word problems involving functions.