Math Problem Statement

Activity 6: Quadratic Functions with multiple sub-questions.

Solution

Here is the solution for each question:

1. The graph of the parabola f(x)=3(x4)2+5f(x) = 3(x - 4)^2 + 5 opens upward

  • The parabola opens upward if the coefficient of (xh)2(x - h)^2 is positive.
  • Here, the coefficient is 33, which is positive.
  • Answer: True (A)

2. What is the axis of symmetry of y=3x26x+4y = 3x^2 - 6x + 4?

  • The axis of symmetry for a parabola in the form y=ax2+bx+cy = ax^2 + bx + c is given by: x=b2ax = -\frac{b}{2a}
  • Here, a=3a = 3, b=6b = -6, so: x=623=66=1x = -\frac{-6}{2 \cdot 3} = \frac{6}{6} = 1
  • Answer: x=1x = 1 (B)

3. If y=x26x+4y = x^2 - 6x + 4, find the vertex

  • The x-coordinate of the vertex is the same as the axis of symmetry: x=b2a=1x = -\frac{b}{2a} = 1
  • Substitute x=1x = 1 into y=x26x+4y = x^2 - 6x + 4: y=(1)26(1)+4=16+4=1y = (1)^2 - 6(1) + 4 = 1 - 6 + 4 = -1
  • The vertex is (1,1)(1, -1).
  • Answer: Not listed (vertex is (1,1)(1, -1)).

4. Solve x24x<5x^2 - 4x < 5

  • Rearrange as x24x5<0x^2 - 4x - 5 < 0.
  • Factorize: (x5)(x+1)<0(x - 5)(x + 1) < 0.
  • Solve the inequality: x(1,5)x \in (-1, 5)
  • Answer: (1,5)(-1, 5) (B)

5. Find the equation of the parabola with vertex (3,2)(3, 2) and x-intercept 44

  • Vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex.
  • Substitute (h,k)=(3,2)(h, k) = (3, 2): y=a(x3)2+2y = a(x - 3)^2 + 2
  • Use the x-intercept (4,0)(4, 0): 0=a(43)2+2    0=a(1)2+2    a=20 = a(4 - 3)^2 + 2 \implies 0 = a(1)^2 + 2 \implies a = -2
  • Equation: y=2(x3)2+2y = -2(x - 3)^2 + 2.
  • Expand to match options: y=2(x26x+9)+2=2x2+12x18+2=2x2+12x16y = -2(x^2 - 6x + 9) + 2 = -2x^2 + 12x - 18 + 2 = -2x^2 + 12x - 16
  • Answer: y=2x2+12x16y = -2x^2 + 12x - 16 (A)

Let me know if you need detailed steps for any solution! Here are related questions to deepen your understanding:

  1. What is the general formula for determining the vertex of a quadratic function in standard form?
  2. How do you determine whether a parabola opens upward or downward?
  3. Can you explain how to factorize quadratic expressions in inequalities?
  4. What is the significance of the axis of symmetry in the graph of a parabola?
  5. How do you derive the vertex form of a parabola from its general equation?

Tip: Always double-check calculations for a,b,a, b, and cc in quadratic functions to avoid simple algebraic errors.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Vertex Form
Axis of Symmetry
Factoring Quadratic Inequalities
Parabola Equation Derivation

Formulas

Axis of symmetry: x = -b/(2a)
Vertex form of a parabola: y = a(x - h)^2 + k
Quadratic inequality solving through factoring

Theorems

Parabola opens upwards if a > 0, downwards if a < 0
Axis of symmetry passes through the vertex
Factoring quadratic expressions to solve inequalities

Suitable Grade Level

Grades 8-10