The graph shows a quadratic function with a vertex at $(-3, 3)$. Since the parabola opens upwards (it has a "U" shape), we can determine the following:

Domain:

The domain of a quadratic function is always all real numbers because a parabola extends infinitely to the left and right. Therefore, the domain in interval notation is: $\boxed{(-\infty, \infty)}$

Range:

The range of the function is determined by the lowest point on the graph, which is the y-coordinate of the vertex. Since the parabola opens upwards, the minimum value of $y$ is 3 (the y-coordinate of the vertex), and the function takes on all values greater than or equal to this point. Therefore, the range in interval notation is: $\boxed{[3, \infty)}$

Would you like further details on how to derive this?

Here are five related questions for further practice:

1. What is the axis of symmetry of the parabola?
2. How do you find the vertex form of a quadratic function given the vertex?
3. What is the effect of changing the vertex on the graph of a parabola?
4. How would the domain and range change if the parabola opened downward instead of upward?
5. Can you determine the equation of the parabola from the given graph?

Tip: The range of a parabola is always influenced by whether it opens upwards or downwards. The vertex will either be a minimum (for upward-opening) or maximum (for downward-opening).