Math Problem Statement

f(x)=2x(to the power of)2 - 3x - 2

Solution

The given function is:

f(x)=2x23x2f(x) = 2x^2 - 3x - 2

This is a quadratic function, which has the general form:

f(x)=ax2+bx+cf(x) = ax^2 + bx + c

Where:

  • a=2a = 2
  • b=3b = -3
  • c=2c = -2

Common tasks for quadratic functions include:

  1. Finding the vertex (the highest or lowest point depending on the parabola's direction).
  2. Determining the roots or solving for x (the values of xx where f(x)=0f(x) = 0).
  3. Finding the axis of symmetry.

Would you like to explore any of these or something else related to this function?

Some related questions:

  1. What is the vertex of this quadratic function?
  2. How do you find the roots of the quadratic equation 2x23x2=02x^2 - 3x - 2 = 0?
  3. What is the axis of symmetry for the quadratic function f(x)=2x23x2f(x) = 2x^2 - 3x - 2?
  4. How do you graph the quadratic function f(x)=2x23x2f(x) = 2x^2 - 3x - 2?
  5. What does the discriminant of the quadratic equation tell you about the roots?

Tip: The axis of symmetry of a quadratic function can be found using the formula x=b2ax = \frac{-b}{2a}.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Parabolas

Formulas

Quadratic function: f(x) = ax^2 + bx + c
Axis of symmetry: x = -b / (2a)
Quadratic formula: x = (-b ± sqrt(b^2 - 4ac)) / (2a)

Theorems

Quadratic Formula
Vertex Formula

Suitable Grade Level

Grades 8-10