It looks like you have a quadratic equation modeling the height of a ball over time, and you're asked to solve for different height values using the quadratic formula. The equation provided is:

$s(t) = -16t^2 + 70t + 5$

where $s(t)$ is the height of the ball in feet, and $t$ is the time in seconds. You have three parts of the problem to solve:

(a) When will the height of the ball be 50 feet?

To solve this, substitute $s(t) = 50$ into the equation and solve for $t$:

$50 = -16t^2 + 70t + 5$

Rearrange to get the quadratic form: $-16t^2 + 70t - 45 = 0$

Use the quadratic formula: $t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ where $a = -16$, $b = 70$, and $c = -45$.

(b) When will the height of the ball be 70 feet?

Substitute $s(t) = 70$ into the equation and solve for $t$: $70 = -16t^2 + 70t + 5$ Simplify: $-16t^2 + 70t - 65 = 0$

Solve this using the quadratic formula.

(c) Will the ball ever reach a height of 140 feet?

Substitute $s(t) = 140$ into the equation: $140 = -16t^2 + 70t + 5$ Rearrange: $-16t^2 + 70t - 135 = 0$

Solve this using the quadratic formula.

Would you like me to go ahead and solve these for you?