Math Problem Statement

Find the value of x in the triangle shown below, given a right triangle with legs x, 4, and hypotenuse 5.

Solution

We are tasked with finding the value of xx in the given right triangle.

Step-by-Step Solution:

We are given:

  • One leg of the triangle: xx (unknown),
  • The other leg: 44,
  • The hypotenuse: 55.

Since this is a right triangle, we can use the Pythagorean Theorem: a2+b2=c2a^2 + b^2 = c^2 Where:

  • aa and bb are the legs,
  • cc is the hypotenuse.

Substitute the known values: x2+42=52x^2 + 4^2 = 5^2

  1. Simplify the squares: x2+16=25x^2 + 16 = 25

  2. Solve for x2x^2 by subtracting 16 from both sides: x2=2516x^2 = 25 - 16 x2=9x^2 = 9

  3. Take the square root of both sides: x=9x = \sqrt{9} x=3x = 3

Final Answer:

The value of xx is 33.

The correct option is: C) x=3x = 3.


Do you want further explanations on the Pythagorean theorem or any other steps? Let me know!

Here are 5 related questions you can explore:

  1. What is the Pythagorean theorem, and how is it derived?
  2. How do you determine if a triangle is a right triangle using its side lengths?
  3. If two sides of a right triangle are given, how do you find the third?
  4. How does the Pythagorean theorem apply to real-world problems?
  5. What are Pythagorean triples, and can you identify examples?

Tip: In a right triangle, always remember the hypotenuse is the longest side and opposite the right angle!

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Pythagorean Theorem

Formulas

Pythagorean Theorem: a^2 + b^2 = c^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 6-8