from sympy import symbols, Eq, solve

Define the variables

x = symbols('x')

Hypotenuse is 4, one leg is 2, and we solve for the other leg x.

hypotenuse = 4 leg1 = 2

Apply the Pythagorean theorem: x^2 + leg1^2 = hypotenuse^2

equation = Eq(x2 + leg12, hypotenuse**2)

Solve for x

solution = solve(equation, x) solution[-2sqrt(3), 2sqrt(3)][-2sqrt(3), 2sqrt(3)]successThe solution to the equation for $x$ is:

$x = 2\sqrt{3}$

(Since $x$ represents a length, we discard the negative root.)

Would you like more details about the solution or related concepts? Here are some related questions:

1. How does the Pythagorean theorem work in general?
2. What is the value of $\sqrt{3}$ approximately?
3. Can the triangle's area be calculated now?
4. What are other applications of the Pythagorean theorem?
5. How do we determine whether a triangle is right-angled using its sides?

Tip: The square root of 3 is approximately 1.732, useful for practical calculations!