The image contains a geometric diagram of a triangle, along with some given conditions in Hebrew, which translate as:

Given:

1. $DF = EF$
2. $AD = AE$
3. $BE = DC$

To prove:

Based on the given information, the problem appears to be focused on proving congruence between certain triangles or segments of the larger triangle, potentially leveraging symmetry and congruent triangles.

To proceed, here are possible steps to approach the proof:

1. Use Symmetry:

   • Since $DF = EF$ and $AD = AE$, triangle $\triangle ADF$ should be congruent to triangle $\triangle AEF$ by the Side-Side-Side (SSS) criterion.

2. Consider Midpoints:

   • The equalities $DF = EF$ and $AD = AE$ suggest symmetry at point $F$, which may indicate that $F$ is a midpoint or a point of intersection with certain symmetrical properties.

3. Analyze Other Equalities:

   • The condition $BE = DC$ implies some relation between the sides of triangles $\triangle ABE$ and $\triangle ACD$. It could be that these triangles are congruent or that some proportional relationship exists, which needs to be proved.

Would you like me to help formalize a step-by-step proof, or would you prefer details on a specific part of the problem?

Here are five related questions that could help expand your understanding:

1. How does the condition $DF = EF$ contribute to proving the congruence of the triangles?
2. What geometric properties arise from the fact that $AD = AE$?
3. Could you use a common center or symmetry argument at point $F$ for the proof?
4. How does the condition $BE = DC$ suggest further relationships between the triangles?
5. What additional geometric theorems (such as SAS or ASA) might apply in this case?

Tip: Always check for possible equal angles when side lengths are given, as it can often lead to proving triangle congruence.