show that underoot(sec^2(x) -1) + underoot(cosec^2(x)-1) = sec(x)cosec(x)

To prove that:

\[
\sqrt{\sec^2(x) - 1} + \sqrt{\cosec^2(x) - 1} = \sec(x)\cosec(x)
\]

### Step 1: Simplifying each term
Start by recalling the following trigonometric identities:

\[
\sec^2(x) - 1 = \tan^2(x)
\]
\[
\cosec^2(x) - 1 = \cot^2(x)
\]

So, the left-hand side becomes:

\[
\sqrt{\sec^2(x) - 1} = \sqrt{\tan^2(x)} = |\tan(x)| = \tan(x) \quad (\text{since } \tan(x) \geq 0 \text{ in the given domain})
\]
\[
\sqrt{\cosec^2(x) - 1} = \sqrt{\cot^2(x)} = |\cot(x)| = \cot(x) \quad (\text{since } \cot(x) \geq 0 \text{ in the given domain})
\]

Thus, the left-hand side becomes:

\[
\tan(x) + \cot(x)
\]

### Step 2: Express the Right-Hand Side
The right-hand side of the equation is:

\[
\sec(x)\cosec(x)
\]

Now, express \(\sec(x)\) and \(\cosec(x)\) in terms of sine and cosine:

\[
\sec(x) = \frac{1}{\cos(x)} \quad \text{and} \quad \cosec(x) = \frac{1}{\sin(x)}
\]

Thus, the right-hand side becomes:

\[
\sec(x)\cosec(x) = \frac{1}{\cos(x)} \cdot \frac{1}{\sin(x)} = \frac{1}{\cos(x)\sin(x)}
\]

### Step 3: Equating the Two Sides
Now, we need to show that:

\[
\tan(x) + \cot(x) = \frac{1}{\cos(x)\sin(x)}
\]

We know that:

\[
\tan(x) = \frac{\sin(x)}{\cos(x)} \quad \text{and} \quad \cot(x) = \frac{\cos(x)}{\sin(x)}
\]

Thus:

\[
\tan(x) + \cot(x) = \frac{\sin(x)}{\cos(x)} + \frac{\cos(x)}{\sin(x)}
\]

Take the common denominator:

\[
\tan(x) + \cot(x) = \frac{\sin^2(x) + \cos^2(x)}{\sin(x)\cos(x)}
\]

Using the Pythagorean identity \(\sin^2(x) + \cos^2(x) = 1\), this simplifies to:

\[
\tan(x) + \cot(x) = \frac{1}{\sin(x)\cos(x)}
\]

This is exactly the same as the right-hand side of the equation.

### Conclusion:
Thus, we have shown that:

\[
\sqrt{\sec^2(x) - 1} + \sqrt{\cosec^2(x) - 1} = \sec(x)\cosec(x)
\]

### Do you have any questions or would you like more details on any specific part of this explanation?

### Relative Questions:
1. What are the basic trigonometric identities?
2. How do you derive the secant and cosecant functions from sine and cosine?
3. What is the Pythagorean identity in trigonometry?
4. Can the tangent and cotangent be expressed in other ways using sine and cosine?
5. How do we handle absolute values in trigonometric identities?
6. What are some other common trigonometric identities used in calculus?
7. How can you prove the identity \(\sin^2(x) + \cos^2(x) = 1\)?
8. What happens if you change the domain for \(\tan(x)\) and \(\cot(x)\)?

### Tip:
Always break down complex trigonometric identities by simplifying each component step-by-step using known identities.

Learn how to prove the trigonometric identity sqrt(sec^2(x) - 1) + sqrt(cosec^2(x) - 1) = sec(x)cosec(x) with a detailed step-by-step solution. This problem involves using trigonometric identities and the Pythagorean identity. Suitable for high school and above.

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