Math Problem Statement
Let ∼ be a relation defined on Z by a∼v if 2a+b ≡ 0(mod 3). Prove it is an equivalent relation.
Solution
To prove that the relation defined on by if is an equivalence relation, we need to verify that it satisfies the three properties of an equivalence relation: reflexivity, symmetry, and transitivity.
1. Reflexivity:
A relation is reflexive if for all .
- For , we need , which simplifies to:
- Since is always divisible by 3 for any integer , the condition holds true. Thus, the relation is reflexive.
2. Symmetry:
A relation is symmetric if .
- Assume , meaning . Rewriting, we get:
- To check symmetry, we must show that , i.e., . Substituting into , we have:
- Thus, , and the relation is symmetric.
3. Transitivity:
A relation is transitive if and .
- Assume and . From , we know: From , we know:
- Substituting into , we get: Since (as ), we have .
- To verify , substitute back into :
- Thus, , and the relation is transitive.
Conclusion:
Since the relation satisfies reflexivity, symmetry, and transitivity, it is an equivalence relation.
Do you have any questions or want further clarification? Here are some related questions to explore:
- Can you provide examples of equivalence classes under this relation?
- How do equivalence classes partition ?
- Can this relation be generalized for -modular arithmetic?
- What is the significance of defining relations over modular arithmetic?
- How would the proof change if the relation were defined differently, such as ?
Tip: Always check each property of an equivalence relation carefully, as skipping one can lead to incomplete proofs.
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Math Problem Analysis
Mathematical Concepts
Equivalence Relations
Modular Arithmetic
Properties of Relations (Reflexivity, Symmetry, Transitivity)
Formulas
2a + b ≡ 0 (mod 3)
3a ≡ 0 (mod 3)
b ≡ -2a (mod 3)
c ≡ -2b (mod 3)
Theorems
Equivalence Relation Definition
Properties of Modular Arithmetic
Suitable Grade Level
Undergraduate Mathematics or Advanced High School
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