Math Problem Statement

Let ∼ be a relation defined on Z by a∼v if 2a+b ≡ 0(mod 3). Prove it is an equivalent relation.

Solution

To prove that the relation \sim defined on Z\mathbb{Z} by aba \sim b if 2a+b0(mod3)2a + b \equiv 0 \pmod{3} is an equivalence relation, we need to verify that it satisfies the three properties of an equivalence relation: reflexivity, symmetry, and transitivity.


1. Reflexivity:

A relation is reflexive if aaa \sim a for all aZa \in \mathbb{Z}.

  • For aaa \sim a, we need 2a+a0(mod3)2a + a \equiv 0 \pmod{3}, which simplifies to: 3a0(mod3).3a \equiv 0 \pmod{3}.
  • Since 3a3a is always divisible by 3 for any integer aa, the condition holds true. Thus, the relation is reflexive.

2. Symmetry:

A relation is symmetric if ab    baa \sim b \implies b \sim a.

  • Assume aba \sim b, meaning 2a+b0(mod3)2a + b \equiv 0 \pmod{3}. Rewriting, we get: 2a+b0(mod3)    b2a(mod3).2a + b \equiv 0 \pmod{3} \implies b \equiv -2a \pmod{3}.
  • To check symmetry, we must show that bab \sim a, i.e., 2b+a0(mod3)2b + a \equiv 0 \pmod{3}. Substituting b2a(mod3)b \equiv -2a \pmod{3} into 2b+a2b + a, we have: 2(2a)+a4a+a3a0(mod3).2(-2a) + a \equiv -4a + a \equiv -3a \equiv 0 \pmod{3}.
  • Thus, bab \sim a, and the relation is symmetric.

3. Transitivity:

A relation is transitive if aba \sim b and bc    acb \sim c \implies a \sim c.

  • Assume aba \sim b and bcb \sim c. From aba \sim b, we know: 2a+b0(mod3)    b2a(mod3).2a + b \equiv 0 \pmod{3} \implies b \equiv -2a \pmod{3}. From bcb \sim c, we know: 2b+c0(mod3)    c2b(mod3).2b + c \equiv 0 \pmod{3} \implies c \equiv -2b \pmod{3}.
  • Substituting b2a(mod3)b \equiv -2a \pmod{3} into c2b(mod3)c \equiv -2b \pmod{3}, we get: c2(2a)4a(mod3).c \equiv -2(-2a) \equiv 4a \pmod{3}. Since 4aa(mod3)4a \equiv a \pmod{3} (as 41(mod3)4 \equiv 1 \pmod{3}), we have ca(mod3)c \equiv a \pmod{3}.
  • To verify aca \sim c, substitute back into 2a+c2a + c: 2a+c2a+a3a0(mod3).2a + c \equiv 2a + a \equiv 3a \equiv 0 \pmod{3}.
  • Thus, aca \sim c, and the relation is transitive.

Conclusion:

Since the relation \sim satisfies reflexivity, symmetry, and transitivity, it is an equivalence relation.


Do you have any questions or want further clarification? Here are some related questions to explore:

  1. Can you provide examples of equivalence classes under this relation?
  2. How do equivalence classes partition Z\mathbb{Z}?
  3. Can this relation be generalized for nn-modular arithmetic?
  4. What is the significance of defining relations over modular arithmetic?
  5. How would the proof change if the relation were defined differently, such as a+b0(mod3)a + b \equiv 0 \pmod{3}?

Tip: Always check each property of an equivalence relation carefully, as skipping one can lead to incomplete proofs.

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Math Problem Analysis

Mathematical Concepts

Equivalence Relations
Modular Arithmetic
Properties of Relations (Reflexivity, Symmetry, Transitivity)

Formulas

2a + b ≡ 0 (mod 3)
3a ≡ 0 (mod 3)
b ≡ -2a (mod 3)
c ≡ -2b (mod 3)

Theorems

Equivalence Relation Definition
Properties of Modular Arithmetic

Suitable Grade Level

Undergraduate Mathematics or Advanced High School