Math Problem Statement
Prove that for every prime p > 5 either *p^*2 − 1 or *p^*2 + 1 is divisible by 10. (You might want to use
mod 5 or mod 10 arithmetic.)
Solution
To prove that for every prime , either or is divisible by 10, we can proceed by considering the properties of prime numbers modulo 10.
Step 1: Consider the possible values of modulo 10
Since is a prime greater than 5, the possible values of modulo 10 are: This is because primes cannot be even, so is not congruent to 0, 2, 4, 6, or 8 modulo 10. Also, cannot be 5 modulo 10 since we are considering primes greater than 5.
Step 2: Calculate modulo 10
For each of the possible values of modulo 10, we calculate modulo 10:
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If : Then, So, is divisible by 10.
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If : Then, So, is divisible by 10.
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If : Then, So, is divisible by 10.
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If : Then, So, is divisible by 10.
Conclusion
In all cases, either or is divisible by 10 for primes .
Therefore, we have proven that for every prime , either or is divisible by 10.
Do you want any more details or have any questions?
Related Questions:
- How does modulo arithmetic help in proving divisibility properties?
- Can we extend this proof to all odd numbers greater than 5, not just primes?
- What are the properties of primes modulo small numbers like 10 or 5?
- How do different modulo systems (e.g., mod 3, mod 4) affect similar proofs?
- What is the significance of quadratic residues in number theory?
- How does this property relate to the properties of twin primes?
- Can we derive any similar divisibility rules using mod 12 or mod 15?
- Is there a generalized form of this proof for primes of the form ?
Tip: When working with modulo arithmetic, it is often helpful to test your hypotheses on small cases before generalizing, as it can provide insights into the underlying patterns.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Modulo Arithmetic
Prime Numbers
Formulas
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Theorems
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Suitable Grade Level
Advanced High School
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