Math Problem Statement

"ask: Brad has five weeks to prepare for his driving exam. His mother volunteered to drive with him for 15 minutes or half an hour each day until the exam, but no more than 15 hours in total. Show that during some period of consecutive days, Brad and his mother will drive for exactly eight and three-quarters hours.

Answer: The driving time is represented as S1, S2, S3, S4, ..., S35, where Sn is the total driving time from the first to the n-th day. We need to prove that there exists S(i) - S(j) = 8.75 (where i < j), as this means the subtotal from day i + 1 to day j. Each Sn mod 8.75 gives remainders in the range [0, 8.75), leading to 35 different values.

Thus, we have 35 cumulative sums (S1, S2, etc.) and 35 possible remainders. Let's consider two cases:

If there are at least two sums S(i) and S(j) that have the same remainder. Then S(i) = S(j) mod 8.75 ==> S(i) - S(j) = k * 8.75, where k is an integer. Since the total driving time is no more than 15, k must equal one, and thus S(i) - S(j) = 8.75, which is what we needed to prove.

If there are no two sums that have the same remainder, then there is a remainder from dividing Si by 8.75 that is guaranteed to be 0, which means Si = 8.75k for some integer k. Again, since k = 2 would exceed the limit of 15 hours (8.75 * 2 = 17.5 > 15), the only option for k is 1, which means Si = 8.75, indicating that the cumulative sum from day 1 to day i equals 8.75.

There are 35 sums and 35 different possible values when divided by 8.75. In the first case, we consider the scenario where there are 2 sums with the same remainder when divided by 8.75. In the second case, when there are no sums with the same remainder when divided by 8.75, this means that all 35 sums have a unique remainder when divided by 8.75 (which in turn also equals 35), meaning there is such a sum that when divided by 8.75 has a remainder of zero, which means Si = 8.75, indicating that the sum from day 1 to day i equals 8.75." explain answer

Solution

The explanation revolves around the Pigeonhole Principle and the concept of remainders when dividing by 8.75. Here's a step-by-step breakdown of the reasoning:


Key Setup

  1. Total Driving Time Boundaries:

    • Brad drives for 15 minutes (0.25 hours) or 30 minutes (0.5 hours) each day.
    • Over 35 days, the total driving time cannot exceed 15 hours.
  2. Cumulative Driving Times:

    • Define SnS_n as the total driving time from the first day to the nn-th day.
    • For example, S1S_1 = driving time on Day 1, S2=S1+Day 2 driving timeS_2 = S_1 + \text{Day 2 driving time}, and so on.
  3. Objective:

    • Prove that there exists a period of consecutive days during which the total driving time equals exactly 8.75 hours.

Using Modular Arithmetic

The critical observation is to consider the cumulative sums S1,S2,,S35S_1, S_2, \dots, S_{35} mod 8.75 (i.e., the remainder when dividing each cumulative sum by 8.75). This creates 35 cumulative sums and 35 possible remainders within the range [0,8.75)[0, 8.75).


Case Analysis

Case 1: Two Sums Have the Same Remainder Modulo 8.75

  • If two cumulative sums SiS_i and SjS_j (where i<ji < j) have the same remainder when divided by 8.75, then: SiSj(mod8.75)S_i \equiv S_j \pmod{8.75} Subtracting these: SjSi=k8.75S_j - S_i = k \cdot 8.75 Since the total driving time is at most 15 hours, the only feasible value of kk is 1 (as 28.75=17.52 \cdot 8.75 = 17.5, which exceeds 15 hours). Thus: SjSi=8.75S_j - S_i = 8.75 This means that the driving time from Day i+1i+1 to Day jj is exactly 8.75 hours.

Case 2: No Two Sums Have the Same Remainder Modulo 8.75

  • If all 35 cumulative sums have unique remainders modulo 8.75, then one of these remainders must be 0 (since there are 35 possible sums and 35 possible remainders, including 0).
  • A remainder of 0 implies: Si=8.75kS_i = 8.75 \cdot k For k=1k = 1, Si=8.75S_i = 8.75, which directly shows that the cumulative driving time from Day 1 to Day ii is exactly 8.75 hours.

Why This Covers All Possibilities

  • Either two sums share a remainder modulo 8.75 (Case 1), or all sums have unique remainders (Case 2). In both cases, we demonstrate that there exists a period where the driving time totals 8.75 hours.

Final Remark

The Pigeonhole Principle ensures the logic is exhaustive:

  • There are 35 cumulative sums and 35 remainders, meaning at least one of the above cases must occur. In both cases, we achieve the desired result.

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Math Problem Analysis

Mathematical Concepts

Modular Arithmetic
Cumulative Sums
Pigeonhole Principle

Formulas

Sn mod 8.75
Si - Sj = k * 8.75

Theorems

Pigeonhole Principle

Suitable Grade Level

Grades 10-12