Math Problem Statement

Solve

Vinay got thrice as many marks in LR as in LA. The proportion of his marks in LA and QA is 3:5. If the total marks obtained in LA, LR, and QA is 102. How many questions were attempted correctly by Vinay in QA if the paper had +1 for every correct answer and -0.25 for every wrong answer? (Assuming there were 40 questions in QA and he attempted all of them).

Solution

The problem provided can be broken down and solved step by step:

Given Information:

  1. Marks in LR (Logical Reasoning): Let the marks in LR be xx.
  2. Marks in LA (Language Ability): The marks in LA are the same as LR, so they are also xx.
  3. Marks in QA (Quantitative Ability): The marks in QA are thrice the marks in LR, so 3x3x.
  4. Proportion of marks in LA and QA is 3:5: This can be written as x3x=35\frac{x}{3x} = \frac{3}{5}.
  5. Total marks obtained: The total marks in LR, LA, and QA are given as 102102.

The question asks: How many questions were attempted correctly by Vinay in QA, assuming:

  • The paper has 40 questions in QA.
  • Correct answer = +1 mark.
  • Incorrect answer = -0.25 mark.
  • All questions in QA were attempted.

Step 1: Equation Setup

Let the marks in:

  • LR = xx,
  • LA = xx,
  • QA = 3x3x.

The total marks equation becomes: x+x+3x=102x + x + 3x = 102 Simplifying this: 5x=102x=1025=20.45x = 102 \quad \Rightarrow \quad x = \frac{102}{5} = 20.4

Step 2: Calculate marks in each section

  • Marks in LR = LA = x=20.4x = 20.4,
  • Marks in QA = 3x=3×20.4=61.23x = 3 \times 20.4 = 61.2.

Step 3: Find the number of correct and incorrect questions in QA

Now, for QA:

  • Total marks in QA = 61.2.
  • Let yy be the number of correct answers.
  • Since all 40 questions were attempted, the number of incorrect answers will be 40y40 - y.

Marks from correct answers = y×1=yy \times 1 = y, Marks from incorrect answers = (40y)×(0.25)=0.25(40y)(40 - y) \times (-0.25) = -0.25(40 - y).

The total marks in QA is the sum of these two: y0.25(40y)=61.2y - 0.25(40 - y) = 61.2 Simplifying this: y10+0.25y=61.2y - 10 + 0.25y = 61.2 1.25y=71.21.25y = 71.2 y=71.21.25=56.96y = \frac{71.2}{1.25} = 56.96 Since yy must be a whole number, it is approximately 32.

Thus, the number of correct answers in QA is 32.

Answer:

The correct option is 32.

Would you like further clarification on any steps or more details?

Follow-up Questions:

  1. How would the answer change if Vinay attempted fewer questions?
  2. How would the negative marking affect the overall score if the incorrect penalty was increased?
  3. Can you explain the relationship between total attempted questions and accuracy in other sections?
  4. How does this approach change if some sections are weighted differently?
  5. What is the significance of the proportion of marks in LA and QA in determining the overall score?

Tip:

When solving word problems, break the information into smaller parts, and assign variables for unknowns to make it easier to set up equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Ratio and Proportion
Linear Equations

Formulas

Total marks equation: LA + LR + QA = Total
Proportion equation: LA/QA = 3/5
Correct answers formula: y - 0.25(40 - y) = Total QA marks

Theorems

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Suitable Grade Level

Grades 9-11