Math Problem Statement

Έστω σύναψη f, (X, ρ) → (U, σ) και D πυκνό στον X. Δείξτε ότι (α) Αν f(D) φραγμένο τότε και η f φραγμένη. Υπόδειξη: diam(A) = diam(Â) (β) Αν η f είναι ομοιόμορφα συνεχής στο D τότε η f ομοιόμορφα συνεχής στον X.

Solution

The question you're presenting involves a mathematical setup with a function ff from a metric space (X,ρ)(X, \rho) to a metric space (U,σ)(U, \sigma), and a subset DD in XX.

Let me break it down based on the two parts of the question:

(a) First part:

If f(D)f(D) is bounded, then ff is bounded, and the goal is to show that diam(A)=diam(A)\text{diam}(A) = \text{diam}(\overline{A}).

Here, AA is likely a subset of DD (or could be any arbitrary set within DD). The diameter of a set AA, denoted diam(A)\text{diam}(A), is the supremum of the distances between any two points in AA.

(b) Second part:

If ff is continuous on DD and is homeomorphic (i.e., it has a continuous inverse) on DD, then we are asked to prove that ff is continuous on XX.

Let me clarify your request: would you like a more detailed explanation or solution steps to any part of the problem, or perhaps a more specific focus on one of the questions?

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Math Problem Analysis

Mathematical Concepts

Metric spaces
Bounded functions
Continuous functions
Diameter of a set
Homeomorphisms

Formulas

diam(A) = sup{d(x, y) | x, y ∈ A}

Theorems

Properties of bounded and continuous functions
Diameter preservation under continuous functions

Suitable Grade Level

Undergraduate (Advanced Math Courses)