Math Problem Statement

DML2-1-stirling.pdf

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Solution

The document is a mathematics assignment focused on proving Stirling's formula for approximating factorials:

n!2πn(ne)nn! \sim \sqrt{2\pi n} \left(\frac{n}{e}\right)^n

The assignment is divided into sections, with each part building on the previous to develop this proof.

Overview of Sections:

  1. A Convergent Sequence:

    • Defines sequences (un)n1(u_n)_{n \geq 1}, (vn)n1(v_n)_{n \geq 1}, and (wn)n2(w_n)_{n \geq 2}.
    • Key Tasks:
      • Prove a formula for wnw_n and use it to find a simple equivalent for (wn)n2(w_n)_{n \geq 2}.
      • Show that the series wn\sum w_n converges and deduce that (un)n1(u_n)_{n \geq 1} converges to a real λ>0\lambda > 0.
      • Conclude that n!λn(ne)nn! \sim \lambda \sqrt{n} \left(\frac{n}{e}\right)^n.
  2. A Sequence of Integrals:

    • Defines Wn=0π2sinn(t)dtW_n = \int_0^{\frac{\pi}{2}} \sin^n(t) \, dt for all nNn \in \mathbb{N}.
    • Key Tasks:
      • Calculate W0W_0 and W1W_1.
      • Develop a recurrence relation for WnW_n using integration by parts.
      • Prove by induction that specific formulas hold for even and odd terms in the sequence WnW_n.
  3. An Equivalent of the Integral:

    • Examines the behavior of (Wn)n0(W_n)_{n \geq 0} and shows it is decreasing.
    • Key Tasks:
      • Show convergence of WnWn+1\frac{W_n}{W_{n+1}} and determine its limit.
      • Use previous results to conclude that Wnπ2nW_n \sim \sqrt{\frac{\pi}{2n}}.

The goal is to arrive at a final step in which λ=2π\lambda = \sqrt{2\pi}, completing the proof of Stirling's formula.

Would you like to start with a specific question, or do you want an explanation on any part of the assignment?


  1. What is the Stirling approximation used for, and why is it significant?
  2. How does convergence of (wn)(w_n) contribute to proving Stirling's formula?
  3. Why are integrals of the form WnW_n useful in this context?
  4. What is the role of recurrence relations in solving mathematical sequences?
  5. How does proving Wnπ2nW_n \sim \sqrt{\frac{\pi}{2n}} relate to the overall goal?

Tip: When working with factorial approximations, breaking down each part of the approximation can help verify accuracy and understand each component's role in the formula.

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Math Problem Analysis

Mathematical Concepts

Stirling's Formula
Sequences and Series
Integration by Parts
Asymptotic Analysis

Formulas

Stirling's Formula: n! ~ √(2πn) * (n/e)^n
Recurrence relation for W_n: W_n+2 = W_n - ∫_0^π/2 cos²(t) * sin^n(t) dt
Approximation of integral sequence: W_n ~ √(π/(2n))

Theorems

Stirling's Approximation
Convergence of Sequences and Series
Limit of a Sequence

Suitable Grade Level

Undergraduate Mathematics (College Level)