Math Problem Statement
An integral formula for the factorials. For n = 0, 1, . . ., consider In := lim T →∞ ∫ T 0 tne−t dt . Prove by induction that these limits exist, and find their values
Solution
To prove that the limits exist and to find their values, we can proceed step by step.
Step 1: Base Case
Start with . The integral becomes: This is a straightforward integral: As , , so: Thus, the base case holds: .
Step 2: Inductive Step
Now, assume that for some , the following is true: We want to show that the integral for also exists and find its value.
Integral for
Consider the integral: We can integrate by parts, where we let:
- , so that ,
- , so that .
Using the integration by parts formula: we have: Now, evaluate the boundary terms: As , because the exponential decay of dominates any polynomial growth of . So, the boundary term vanishes: Thus, we are left with:
Step 3: Conclusion
By induction, we have shown that for all . Specifically:
- ,
- ,
- ,
- and so on.
Therefore, we conclude:
Would you like a more detailed explanation of any of the steps or further examples? Here are 5 related questions you might find interesting:
- How does the method of integration by parts generalize for higher-order integrals?
- How does the exponential decay affect the convergence of integrals as ?
- What is the relationship between the Gamma function and factorials in terms of integrals?
- Can we derive the factorial expression using a recurrence relation instead of induction?
- How does the integral relate to the Gamma function?
Tip: Whenever you're dealing with limits of integrals involving exponential decay, check if integration by parts can simplify the process and eliminate troublesome terms.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Integral Calculus
Induction
Factorials
Exponential Functions
Formulas
I_n = lim(T→∞) ∫_0^T t^n e^−t dt
Integration by Parts formula: ∫ u dv = uv - ∫ v du
Theorems
Inductive Proof
Factorial Formula
Suitable Grade Level
Grades 11-12 / Undergraduate