Math Problem Statement

Rearrange all the steps to create a proof of the following statement. Proposition: If c is a nonzero real number and (a_n) is a real-valued sequence that converges to a, then the sequence (c a_n) converges to ca.

Solution

It looks like you are working on a proof involving sequences and limits. The statement you need to prove is:

Proposition: If cc is a nonzero real number and (an)(a_n) is a real-valued sequence that converges to aa, then the sequence (can)(c a_n) converges to cac a.

Steps to arrange:

  1. Starting assumptions:

    • (an)(a_n) converges to aa. That means, for any ϵ>0\epsilon > 0, there is an NN such that for all n>Nn > N, ana<ϵ|a_n - a| < \epsilon.
  2. What we need to show:

    • We need to show that (can)(c a_n) converges to cac a. That is, for any ϵ>0\epsilon > 0, we want to find an NN such that for all n>Nn > N, canca<ϵ|c a_n - c a| < \epsilon.
  3. Use properties of limits:

    • Use the fact that canca=cana|c a_n - c a| = |c| \cdot |a_n - a|, since cc is constant and nonzero. We want to show that for sufficiently large nn, cana<ϵ|c| \cdot |a_n - a| < \epsilon.
  4. Choose ϵ\epsilon:

    • Let ϵ=ϵc\epsilon' = \frac{\epsilon}{|c|}. Since anaa_n \to a, there exists an NN such that for all n>Nn > N, ana<ϵ|a_n - a| < \epsilon'.

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Math Problem Analysis

Mathematical Concepts

Sequences
Limits
Real Numbers

Formulas

|c a_n - c a| = |c| |a_n - a|

Theorems

Limit properties (scaling of sequences)

Suitable Grade Level

Undergraduate (Calculus / Real Analysis)