Consider the Cauchy sequences (an)n∈N and (bn)n∈N, show that
1. (an + bn)n∈N,

To show that \((a_n + b_n)_{n \in \mathbb{N}}\) is a Cauchy sequence, we need to use the definition of a **Cauchy sequence**.

### Definition of a Cauchy Sequence:
A sequence \((x_n)_{n \in \mathbb{N}}\) is Cauchy if for every \(\epsilon > 0\), there exists an integer \(N\) such that for all \(m, n \geq N\),
\[
|x_n - x_m| < \epsilon.
\]
Now, we are given that both \((a_n)_{n \in \mathbb{N}}\) and \((b_n)_{n \in \mathbb{N}}\) are Cauchy sequences. This means:
- For every \(\epsilon > 0\), there exists an integer \(N_1\) such that for all \(m, n \geq N_1\),
  \[
  |a_n - a_m| < \frac{\epsilon}{2}.
  \]
- Similarly, for every \(\epsilon > 0\), there exists an integer \(N_2\) such that for all \(m, n \geq N_2\),
  \[
  |b_n - b_m| < \frac{\epsilon}{2}.
  \]

Now, let \(N = \max(N_1, N_2)\). For all \(m, n \geq N\), we have:
\[
|a_n - a_m| < \frac{\epsilon}{2} \quad \text{and} \quad |b_n - b_m| < \frac{\epsilon}{2}.
\]

### Step-by-Step Proof:
Consider the sequence \((a_n + b_n)_{n \in \mathbb{N}}\). We need to show that this sequence is Cauchy. For \(m, n \geq N\), observe the following:
\[
|(a_n + b_n) - (a_m + b_m)| = |(a_n - a_m) + (b_n - b_m)|.
\]

By the **triangle inequality**, we have:
\[
|(a_n + b_n) - (a_m + b_m)| \leq |a_n - a_m| + |b_n - b_m|.
\]

Now, using the fact that both \(|a_n - a_m| < \frac{\epsilon}{2}\) and \(|b_n - b_m| < \frac{\epsilon}{2}\) for all \(m, n \geq N\), we get:
\[
|(a_n + b_n) - (a_m + b_m)| \leq \frac{\epsilon}{2} + \frac{\epsilon}{2} = \epsilon.
\]

Therefore, for all \(m, n \geq N\), we have:
\[
|(a_n + b_n) - (a_m + b_m)| < \epsilon.
\]

This shows that the sequence \((a_n + b_n)_{n \in \mathbb{N}}\) is a Cauchy sequence, since for every \(\epsilon > 0\), there exists an integer \(N\) such that for all \(m, n \geq N\), the difference \(|(a_n + b_n) - (a_m + b_m)|\) is less than \(\epsilon\).

### Conclusion:
\[
(a_n + b_n)_{n \in \mathbb{N}} \quad \text{is a Cauchy sequence.}
\]

Would you like a deeper explanation on any part of this proof or clarification? Here are five related questions:

1. What properties of Cauchy sequences are important for proving convergence?
2. Can the sum of two non-Cauchy sequences ever form a Cauchy sequence?
3. How would this proof change if one sequence were not Cauchy?
4. What role does the triangle inequality play in proofs involving Cauchy sequences?
5. How does the concept of Cauchy sequences relate to completeness in metric spaces?

**Tip:** When adding two Cauchy sequences, the triangle inequality helps break down complex expressions into manageable parts.

Consider the Cauchy sequences (a_n)_{n ∈ N} and (b_n)_{n ∈ N}, show that (a_n + b_n)_{n ∈ N} is also a Cauchy sequence.

Explore a detailed proof showing that the sum of two Cauchy sequences (a_n) and (b_n) is also a Cauchy sequence. Learn key mathematical concepts such as Cauchy sequences, the triangle inequality, and how they contribute to understanding sequence convergence. Suitable for undergraduate students studying real analysis.

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