Math Problem Statement

If f is continuous, show that Z b a f(−x)dx = Z −a −b f(x)dx . When f(x) ≥ 0 and 0 ≤ a < b, draw a picture to interpret this equality as an equality of areas.

Solution

We are asked to prove the equality:

abf(x)dx=abf(x)dx.\int_a^b f(-x) \, dx = \int_{-a}^{-b} f(x) \, dx.

Proof of the Equality

We begin with the left-hand side:

abf(x)dx.\int_a^b f(-x) \, dx.

To change the limits of integration, we perform the substitution u=xu = -x. Then, du=dxdu = -dx, and the limits change as follows:

  • When x=ax = a, u=au = -a.
  • When x=bx = b, u=bu = -b.

Thus, the integral becomes:

abf(x)dx=abf(u)(du).\int_a^b f(-x) \, dx = \int_{-a}^{-b} f(u) (-du).

Since du=dxdu = -dx, we can factor out the negative sign, giving:

abf(u)(du)=baf(u)du.\int_{-a}^{-b} f(u) (-du) = \int_{-b}^{-a} f(u) \, du.

Since uu is a dummy variable (it represents the same thing as xx), we can replace uu with xx again:

baf(u)du=baf(x)dx.\int_{-b}^{-a} f(u) \, du = \int_{-b}^{-a} f(x) \, dx.

Thus, we have shown that:

abf(x)dx=baf(x)dx.\int_a^b f(-x) \, dx = \int_{-b}^{-a} f(x) \, dx.

Finally, we can rewrite the right-hand side of the original expression to match this result:

abf(x)dx=baf(x)dx,\int_{-a}^{-b} f(x) \, dx = \int_{-b}^{-a} f(x) \, dx,

so the equality is proven.

Graphical Interpretation

When f(x)0f(x) \geq 0 and 0a<b0 \leq a < b, the equality can be interpreted as an equality of areas under the curve.

  • The integral abf(x)dx\int_a^b f(-x) \, dx represents the area under the curve of f(x)f(-x), which is a reflection of the function f(x)f(x) across the y-axis, evaluated between aa and bb.
  • The integral abf(x)dx\int_{-a}^{-b} f(x) \, dx represents the area under the curve of f(x)f(x), but between the limits a-a and b-b.

The equality shows that the area under the curve on one side of the y-axis is the same as the area on the other side, reflecting the symmetry in the function when transformed by f(x)f(-x).

Diagram:

The diagram would consist of two areas:

  • One between aa and bb, for the function f(x)f(-x), on the positive side of the x-axis.
  • One between b-b and a-a, for the function f(x)f(x), on the negative side of the x-axis.

The areas under the curves on both sides of the y-axis will be identical if the integral equality holds.


Do you want any further clarifications or a visual representation of the graph?

Here are some related questions:

  1. How does the substitution u=xu = -x work in definite integrals?
  2. What is the significance of continuity in proving integral equalities?
  3. Can you provide an example of a function f(x)f(x) and calculate both integrals?
  4. How does symmetry play a role in interpreting these kinds of integrals?
  5. What would happen if f(x)f(x) were not continuous or had discontinuities?

Tip: When performing a substitution in definite integrals, always adjust the limits of integration accordingly to match the new variable.

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Math Problem Analysis

Mathematical Concepts

Calculus
Definite Integrals
Substitution Method
Symmetry

Formulas

∫(from a to b) f(−x) dx = ∫(from -a to -b) f(x) dx
Substitution u = -x

Theorems

Fundamental Theorem of Calculus
Properties of Definite Integrals

Suitable Grade Level

Undergraduate Calculus