Math Problem Statement
- Just for this question, pretend that 1 as a prime number. It is not actually a prime number, but if we pretend it is for a minute, it makes the following statement easier to write. Bertrand’s postulate is a theorem in number theory which states that for every positive integer n, there is a prime number p such that 1 2 n < p ≤ n. Use Bertrand’s postulate along with strong induction to prove that every integer n ≥ 1 can be written as a sum of distinct primes. “Distinct” means that no prime shows up twice: 9 = 5 + 2 + 2 would not be valid since 2 is repeated, but 9 = 5 + 3 + 1 is valid. A sum with only one term, like 2 = 2, is valid. You do not need to prove Bertrand’s postulat
Solution
To prove that every integer can be written as a sum of distinct primes using strong induction and Bertrand's postulate (with the assumption that 1 is a prime number), we'll proceed as follows.
Step 1: Base Case
For :
- is trivially written as a sum of distinct primes because we are pretending that 1 is a prime number. Thus, can be written as the sum of the distinct prime alone.
Thus, the base case holds.
Step 2: Inductive Hypothesis
Assume that for all integers , where , every integer can be written as a sum of distinct primes. This is the strong induction hypothesis.
Step 3: Inductive Step
We need to prove that can also be written as a sum of distinct primes.
Case 1: is prime
- If is prime, then itself is a valid sum of distinct primes (with only one term). This satisfies the condition that can be written as a sum of distinct primes.
Case 2: is not prime
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If is not prime, then we can use the inductive hypothesis. Since Bertrand’s postulate guarantees that between any number and , there is a prime , we can use this prime number to break down into two smaller distinct primes.
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Let be a prime such that (by Bertrand’s postulate). Now, subtract this prime from . That is: where is a smaller number than .
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By the inductive hypothesis, can be written as a sum of distinct primes, say:
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Hence, can be written as: Since and the primes are distinct, this is a valid sum of distinct primes.
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Conclusion:
By strong induction, we have proven that every integer can be written as a sum of distinct primes. Bertrand’s postulate ensures that we can always find a prime within the appropriate range to apply the inductive step.
Would you like any clarifications or more details on this proof?
Related Questions:
- How does Bertrand's postulate work for large values of ?
- Can you give more examples of writing integers as sums of distinct primes?
- What would change in this proof if we do not treat 1 as a prime number?
- How does strong induction differ from simple induction?
- Can this method be extended to non-prime numbers?
Tip:
When applying strong induction, always carefully verify the base case and ensure that the inductive hypothesis covers all relevant cases up to .
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Math Problem Analysis
Mathematical Concepts
Number Theory
Induction
Prime Numbers
Formulas
Bertrand's Postulate: For every positive integer n, there is a prime number p such that 1/2n < p ≤ n
Theorems
Bertrand's Postulate
Strong Induction
Suitable Grade Level
Grades 11-12 or College-level Number Theory
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