Math Problem Statement

Can you explain this?

Can you explain this?

Solution

This text discusses the proof that every third Fibonacci number is even, using mathematical induction. Let’s break it down step by step for clarity:


Part a: Fibonacci sequence

The sequence f1,f2,f3,f_1, f_2, f_3, \dots is defined as:
f1=1,f2=1,f3=2,f4=3,f5=5,f6=8,f7=13,f8=21,f9=34,f10=55,f11=89,f12=144f_1 = 1, f_2 = 1, f_3 = 2, f_4 = 3, f_5 = 5, f_6 = 8, f_7 = 13, f_8 = 21, f_9 = 34, f_{10} = 55, f_{11} = 89, f_{12} = 144

From this, we observe a pattern:

  • Every third Fibonacci number (e.g., f3=2,f6=8,f9=34,f12=144f_3 = 2, f_6 = 8, f_9 = 34, f_{12} = 144) is even, while the others are odd.

The task is to prove this property for all natural numbers nn.


Part b: Proof by induction

We aim to prove that f3nf_{3n} is even, and f3n2f_{3n - 2} and f3n1f_{3n - 1} are odd for any natural number nn.


1. Base Case (n = 1):

From the sequence:

  • f3=2f_3 = 2 (even),
  • f1=1f_1 = 1 (odd),
  • f2=1f_2 = 1 (odd).

The statement holds for n=1n = 1.


2. Induction Hypothesis:

Assume that for some k1k \geq 1, the following is true:

  • f3k2f_{3k-2} is odd,
  • f3k1f_{3k-1} is odd,
  • f3kf_{3k} is even.

We must show that this implies:

  • f3(k+1)2f_{3(k+1)-2} is odd,
  • f3(k+1)1f_{3(k+1)-1} is odd,
  • f3(k+1)f_{3(k+1)} is even.

3. Induction Step:

The Fibonacci recurrence relation states:
fn+2=fn+1+fnf_{n+2} = f_{n+1} + f_n

Let’s compute f3(k+1)2,f3(k+1)1,f3(k+1)f_{3(k+1)-2}, f_{3(k+1)-1}, f_{3(k+1)}:

  1. f3(k+1)2=f3k+1=f3k+f3k1f_{3(k+1)-2} = f_{3k+1} = f_{3k} + f_{3k-1}:

    • f3kf_{3k} is even, f3k1f_{3k-1} is odd, so their sum is odd.
    • Hence, f3k+1f_{3k+1} is odd.
  2. f3(k+1)1=f3k+2=f3k+1+f3kf_{3(k+1)-1} = f_{3k+2} = f_{3k+1} + f_{3k}:

    • f3k+1f_{3k+1} is odd, f3kf_{3k} is even, so their sum is odd.
    • Hence, f3k+2f_{3k+2} is odd.
  3. f3(k+1)=f3k+3=f3k+2+f3k+1f_{3(k+1)} = f_{3k+3} = f_{3k+2} + f_{3k+1}:

    • Both f3k+2f_{3k+2} and f3k+1f_{3k+1} are odd, so their sum is even.
    • Hence, f3k+3f_{3k+3} is even.

Conclusion:

By induction, f3nf_{3n} is even for all nn, and f3n2f_{3n-2}, f3n1f_{3n-1} are odd for all nn.

This completes the proof.


Summary

  • The proof uses induction on the structure of the Fibonacci sequence.
  • It relies on the recurrence relation and the properties of odd/even numbers under addition.

Would you like further explanation or examples?

Here are 5 related questions to deepen understanding:

  1. What are the properties of Fibonacci numbers regarding divisibility?
  2. How does the modulo operation help identify patterns in sequences?
  3. Can you generalize patterns in Fibonacci numbers for other moduli, like mod 3 or mod 5?
  4. How is mathematical induction used in other proofs for Fibonacci sequences?
  5. Can the proof be adapted for Lucas numbers (a related sequence)?

Tip: Always test small cases when dealing with induction problems to identify patterns or confirm hypotheses.

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Math Problem Analysis

Mathematical Concepts

Fibonacci Sequence
Parity (Odd and Even Numbers)
Mathematical Induction

Formulas

f_{n+2} = f_{n+1} + f_n

Theorems

Properties of Fibonacci Numbers

Suitable Grade Level

Grades 11-12