Math Problem Statement
Solution
The image contains a mathematical statement that needs to be proven. The statement is:
"Prove that ."
This is a well-known identity in set theory called De Morgan's Law.
Proof:
We need to prove that: where:
- and are any two sets.
- denotes the complement of , i.e., the set of all elements that are not in .
- is the union of sets and , meaning all elements that are in or or both.
1. Left-Hand Side ():
The complement of the union consists of all elements that are not in . This means: So, is not in and is not in . This can be written as: Thus: Therefore: So, we have shown that:
2. Right-Hand Side ():
Now, consider the right-hand side, which is .
An element that belongs to must be in both and . This means: Which implies: Therefore, , which means: So, we have shown that:
Conclusion:
Since both and , we conclude that:
This completes the proof.
Would you like any further details or have any questions?
Here are some related questions to explore:
- How do De Morgan's laws extend to more than two sets?
- Can De Morgan's laws be applied to logical statements, and if so, how?
- What is the significance of set complements in probability theory?
- How does the intersection operation differ from the union in set theory?
- Can you provide an example where De Morgan's laws simplify a set expression?
Tip: De Morgan's laws are fundamental in both set theory and logic, helping simplify complex expressions involving unions, intersections, and complements.
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Math Problem Analysis
Mathematical Concepts
Set Theory
De Morgan's Laws
Formulas
\(\overline{A \cup B} = \overline{A} \cap \overline{B}\)
Theorems
De Morgan's Laws
Suitable Grade Level
Grades 11-12