It seems you uploaded the same problem again. The problem discusses two scenarios: a horizontal shot and a shot at an angle.

If you need clarification on any part of the solution or any additional details about this, let me know.

Here’s a brief recap of what we have so far:

Part (a): Horizontal Shot

• Horizontal distance: 10 meters
• Initial velocity: 150 m/s (completely horizontal)
• Time to reach the target: 0.0667 seconds
• Vertical displacement due to gravity: 2.18 cm

Part (b): Angled Shot

• Distance to target: 10 meters
• Initial velocity: 150 m/s
• Angle required to hit the target: Approximately 0.125 degrees.

Let me know if you need further details or calculations, and feel free to ask about any specific step!

Related Questions:

1. What would be the flight time if the target was further away, say 20 meters?
2. How much will the vertical displacement change if the angle of the gun was adjusted slightly?
3. How would the motion change if Yusuf were on a higher or lower platform than the target?
4. What is the maximum possible height reached by the pellet for a given angle?
5. How would a stronger gravitational field affect the outcome?

Tip: The horizontal and vertical components of projectile motion are independent of each other. This principle helps simplify complex motion into more manageable parts!