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To solve this problem, let's analyze the information and questions provided.

### Problem Breakdown
The fireworks are launched from a 100-foot building with an initial velocity of 84 feet per second. The height \( h \) of the fireworks at any time \( t \) seconds after launch is given by the equation:
\[
h = -16t^2 + 84t + 100
\]
Here:
- The term \( -16t^2 \) represents the effect of gravity (in feet per second squared).
- \( 84t \) is the initial velocity component.
- \( 100 \) is the initial height of the building.

Let's address each question one by one.

### Question A: How long are the fireworks in the air?
To find how long the fireworks are in the air, we need to determine when they hit the ground. This happens when the height \( h = 0 \).

1. Set the equation to zero:
   \[
   -16t^2 + 84t + 100 = 0
   \]
2. Solve this quadratic equation for \( t \).

Using the quadratic formula:
\[
t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \( a = -16 \), \( b = 84 \), and \( c = 100 \).

Plugging in the values:
\[
t = \frac{-84 \pm \sqrt{84^2 - 4 \cdot (-16) \cdot 100}}{2 \cdot (-16)}
\]
Calculate the discriminant:
\[
84^2 = 7056 \quad \text{and} \quad 4 \cdot 16 \cdot 100 = 6400
\]
\[
t = \frac{-84 \pm \sqrt{7056 + 6400}}{-32}
\]
\[
t = \frac{-84 \pm \sqrt{13456}}{-32}
\]
Solving this gives two values for \( t \), but we will take the positive value, which represents the time in the air.

### Question B: How high did the fireworks get?
The maximum height is reached at the vertex of the parabola. The time \( t \) at the vertex can be found using:
\[
t = \frac{-b}{2a} = \frac{-84}{2 \cdot (-16)} = \frac{84}{32} = 2.625 \text{ seconds}
\]
Now, substitute \( t = 2.625 \) into the height equation to find the maximum height.

### Question C: How high were the fireworks 2 seconds after they left the roof?
To find the height 2 seconds after launch, substitute \( t = 2 \) into the equation:
\[
h = -16(2)^2 + 84 \cdot 2 + 100
\]
This will give the height at \( t = 2 \) seconds.

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I’ll calculate these values for you if you'd like. Let me know if you want detailed steps for each calculation or if you have questions about any part of the process.

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#### Additional Questions for Deeper Understanding:
1. How would the equation change if the initial velocity were different?
2. What would happen to the height if gravity were stronger (e.g., -20t² instead of -16t²)?
3. How can you determine the initial velocity if only given the maximum height and initial height?
4. Why does the term \( -16t^2 \) affect the height as time progresses?
5. Could we use this formula to model other objects launched upwards? Why or why not?

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**Tip:** Remember that the vertex of a parabolic trajectory represents the maximum point, which is why it’s used to find the highest point in projectile motion problems like this.

Fireworks are fired from the roof of a 100-foot building and travel 84 feet per second. The equation h = -16t^2 + 84t + 100 models the height of the fireworks at any given time t seconds. 

A: How long are the fireworks in the air?
B: How high did the fireworks get?
C: How high were the fireworks 2 seconds after they left the roof?

Learn how to determine the maximum height and duration of fireworks launched from a 100-foot building at 84 feet per second. Using quadratic functions, we solve for the time the fireworks remain in the air, their highest point, and their height after 2 seconds. Ideal for Grades 9-11 students.

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