Math Problem Statement
these are the ranges use them to calaculate 10 degree=0.495m 20 degree=0.715m, 30 degree=0.8675m, 40 degree=0.10m, 45 degree=1m, 50 degree=0.955m, 60 degree=0.6225m, 70 degree=0.52m, 80degree=0.20m these are the given range use to calculate height and time of flight using kinematics equation and put the answers on a table
Solution
import pandas as pd
Given data
angles = [10, 20, 30, 40, 45, 50, 60, 70, 80] ranges = [0.495, 0.715, 0.8675, 0.10, 1.0, 0.955, 0.6225, 0.52, 0.20]
Constants
g = 9.8 # Acceleration due to gravity (m/s^2)
Create a table to calculate time of flight and maximum height
data = [] for angle, range_ in zip(angles, ranges): angle_rad = angle * (3.14159 / 180) # Convert angle to radians # Initial velocity (v0) calculation using the range formula R = (v0^2 * sin(2θ)) / g v0_squared = range_ * g / (2 * (angle_rad % 3.14159)) if angle != 90 else 0 v0 = v0_squared**0.5 if v0_squared > 0 else 0
success# Calculating Time of Flight (T) and Maximum Height (H) for r along system pattern.
Cell In[2], line 2 for r along system pattern. ^ SyntaxError: invalid syntax
failed_with_in_kernel_exceptionIt seems there was a mistake in the computation. Let me recalculate the table systematically using the kinematics equations.import numpy as np
Function to calculate time of flight and maximum height
def calculate_kinematics(angle, range_): angle_rad = np.radians(angle) # Convert angle to radians if angle == 90: # To avoid undefined behavior for vertical launches return 0, 0
# Calculate initial velocity using range equation: R = (v0^2 * sin(2θ)) / g
v0_squared = range_ * g / np.sin(2 * angle_rad)
v0 = np.sqrt(v0_squared) if v0_squared > 0 else 0
# Time of flight: T = 2 * v0 * sin(θ) / g
time_of_flight = (2 * v0 * np.sin(angle_rad)) / g
# Maximum height: H = (v0^2 * sin^2(θ)) / (2 * g)
max_height = (v0**2 * (np.sin(angle_rad)**2)) / (2 * g)
return time_of_flight, max_height
Calculate values for each angle and range
results = [] for angle, range_ in zip(angles, ranges): time_of_flight, max_height = calculate_kinematics(angle, range_) results.append([angle, range_, time_of_flight, max_height])
Create a DataFrame for the results
columns = ["Angle (°)", "Range (m)", "Time of Flight (s)", "Maximum Height (m)"] df = pd.DataFrame(results, columns=columns)
Display the DataFrame to the user
import ace_tools as tools; tools.display_dataframe_to_user(name="Projectile Motion Calculations Table", dataframe=df) Angle (°) Range (m) Time of Flight (s) Maximum Height (m) 0 10 0.4950 0.133464 0.021820 1 20 0.7150 0.230456 0.065060 2 30 0.8675 0.319710 0.125213 3 40 0.1000 0.130861 0.020977 4 45 1.0000 0.451754 0.250000 Angle (°) Range (m) Time of Flight (s) Maximum Height (m) 0 10 0.4950 0.133464 0.021820 1 20 0.7150 0.230456 0.065060 2 30 0.8675 0.319710 0.125213 3 40 0.1000 0.130861 0.020977 4 45 1.0000 0.451754 0.250000successThe calculations for the given angles and ranges have been completed and are presented in the table. Let me know if you'd like further explanation or additional calculations.
5 Related Questions:
- How do these kinematics values change if air resistance is considered?
- Can we derive initial velocity explicitly for each case based on the provided ranges?
- How do time of flight and height correlate with the launch angle?
- What happens to the range and height as the angle approaches 90°?
- How would the experiment change if we varied only the velocity instead of the angle?
Tip:
When solving projectile motion problems, always ensure to convert angles to radians if using trigonometric functions in equations, as most programming libraries default to radian mode.
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Math Problem Analysis
Mathematical Concepts
Projectile Motion
Kinematics
Trigonometry
Formulas
Range formula: R = (v0^2 * sin(2θ)) / g
Time of Flight: T = (2 * v0 * sin(θ)) / g
Maximum Height: H = (v0^2 * sin^2(θ)) / (2 * g)
Theorems
Kinematic Equations of Motion
Trigonometric Identities
Suitable Grade Level
Grades 9-12
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