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The image you provided shows a physics-related problem, particularly about projectile motion. Here's a breakdown of the components of the table and the formulas you might need:

**Key Variables:**
- \( h \): height (assumed to be the initial height from the ground, but not provided in the table).
- \( \theta \): angle of projection.
- \( v_0 \): initial velocity (in m/s).
- \( m \): mass (mass is irrelevant for the calculations since it's not mentioned in the equations).
- \( S_y \): maximum height (vertical displacement to the highest point).
- \( S_x \): range (horizontal distance).
- \( t_{tertinggi} \): time to reach the highest point.
- \( t_{terjauh} \): total time of flight.

The questions ask for the following:

### a) **Maximum Height** \( S_y \)
The formula for the maximum height of a projectile is:
\[
S_y = \frac{{v_0^2 \sin^2(\theta)}}{2g}
\]
where \( g \) is the acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \).

### b) **Horizontal Distance to the Maximum Height** \( S_{x, tertinggi} \)
At the highest point, the horizontal displacement is half of the total range:
\[
S_{x, tertinggi} = v_0 \cos(\theta) \times t_{tertinggi}
\]

### c) **Time to Reach the Maximum Height** \( t_{tertinggi} \)
The time to reach the highest point is:
\[
t_{tertinggi} = \frac{v_0 \sin(\theta)}{g}
\]

### d) **Total Range (Horizontal Distance)** \( S_x \)
The total horizontal range is:
\[
S_x = \frac{{v_0^2 \sin(2\theta)}}{g}
\]

### e) **Total Time of Flight** \( t_{terjauh} \)
The total time of flight is:
\[
t_{terjauh} = \frac{2v_0 \sin(\theta)}{g}
\]

### Example Calculation for Row 1:
For \( \theta = 30^\circ \) and \( v_0 = 15 \, \text{m/s} \):
1. \( S_y = \frac{15^2 \times \sin^2(30^\circ)}{2 \times 9.8} \)
2. \( t_{tertinggi} = \frac{15 \times \sin(30^\circ)}{9.8} \)
3. \( S_x = \frac{15^2 \times \sin(60^\circ)}{9.8} \)
4. \( t_{terjauh} = \frac{2 \times 15 \times \sin(30^\circ)}{9.8} \)

Would you like me to go ahead with detailed calculations for all the rows, or do you need further clarification on the steps?

Here are five follow-up questions to consider:
1. How does changing the angle of projection affect the range of the projectile?
2. Why does mass not play a role in determining the projectile's motion?
3. How would air resistance change the calculated values for range and maximum height?
4. What would happen to the time of flight if the projectile is launched from a higher platform?
5. Can the angle ever be greater than 90 degrees in a projectile motion context?

**Tip:** For smaller angles (like 30°), the range increases with the initial velocity but decreases quickly with higher angles like 60°.

Based on the provided image, fill in the table with the results from your experiment. Calculate the following: a) Maximum height (S_y), b) Horizontal distance to the maximum height (S_x, tertinggi), c) Time to reach the maximum height (t_tertinggi), d) Total range (S_x), e) Total time of flight (t_terjauh).

Learn how to calculate the maximum height, horizontal distance to the maximum height, time to reach the maximum height, total range, and total time of flight for projectile motion. This problem involves key concepts in trigonometry and kinematics, making it suitable for students in grades 10-12.

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