Math Problem Statement
Solution
The problem in the image involves a player shooting a ball at an initial velocity of 20 m/s at an angle of 60 degrees above the horizontal. We are asked to:
- (a) Determine the approximate range of the ball.
- (b) Calculate the maximum height of the ball.
- (c) Find the time it takes for the ball to reach point B from point A (half of the trajectory).
- (d) Find the total time the ball is in motion from point A to point B.
To solve this, we use the following kinematic equations for projectile motion:
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Horizontal and vertical components of velocity: where is the initial speed (20 m/s), and is the angle (60 degrees).
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Range: The range is the horizontal distance the ball travels before hitting the ground: where is the acceleration due to gravity (9.8 m/s²).
-
Maximum height: The maximum height is reached when the vertical component of the velocity becomes zero:
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Time to reach maximum height: The time to reach the highest point (half of the total time) is given by:
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Total flight time: The total flight time is twice the time to reach the maximum height:
Let me compute these values for each part.Here are the results for the projectile motion problem:
- (a) The approximate range of the ball is 35.35 meters.
- (b) The maximum height of the ball is 15.31 meters.
- (c) The time it takes for the ball to reach point B (the highest point) is 1.77 seconds.
- (d) The total flight time for the ball from point A to point B (when it hits the ground again) is 3.53 seconds.
Would you like more details on the calculations or any of the steps?
Here are five related questions for further exploration:
- How would changing the angle of projection affect the range of the ball?
- What would the range be if the initial velocity were increased to 30 m/s?
- How does air resistance impact the calculations in real-world conditions?
- Can you calculate the ball's velocity at different points during its flight?
- How would you calculate the distance at any given time, , during the flight?
Tip: For maximum range in projectile motion, the ideal launch angle is 45 degrees when air resistance is neglected.
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Math Problem Analysis
Mathematical Concepts
Projectile motion
Kinematic equations
Trigonometry
Formulas
v_x = v_0 * cos(θ)
v_y = v_0 * sin(θ)
Range (R) = (v_0^2 * sin(2θ)) / g
Maximum height (H) = (v_0^2 * sin^2(θ)) / 2g
Time to maximum height = (v_0 * sin(θ)) / g
Total flight time = 2 * Time to maximum height
Theorems
Kinematic equations for projectile motion
Trigonometric relations
Suitable Grade Level
High School (Grades 9-12)
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