The problem you've shared involves a projectile motion scenario where a golfer hits a ball at an initial velocity and angle. Let's break down and solve each part step by step using physics principles.

Given:

• Initial velocity $u = 21 \, \text{m/s}$
• Angle $\theta = 60^\circ$
• Gravitational acceleration $g = 9.81 \, \text{m/s}^2$
• The ball is a particle, and air resistance is neglected.

Part a) Find the maximum height of the ball.

To calculate the maximum height, we need to focus on the vertical component of the motion. The initial vertical velocity $u_y$ is given by: $u_y = u \sin\theta = 21 \sin(60^\circ)$

At maximum height, the vertical velocity becomes zero. Using the kinematic equation: [ v_y^2 =