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The problem you've shared involves a projectile motion scenario where a golfer hits a ball at an initial velocity and angle. Let's break down and solve each part step by step using physics principles.

### Given:
- Initial velocity \( u = 21 \, \text{m/s} \)
- Angle \( \theta = 60^\circ \)
- Gravitational acceleration \( g = 9.81 \, \text{m/s}^2 \)
- The ball is a particle, and air resistance is neglected.

#### Part a) Find the maximum height of the ball.

To calculate the maximum height, we need to focus on the vertical component of the motion. The initial vertical velocity \( u_y \) is given by:
\[
u_y = u \sin\theta = 21 \sin(60^\circ)
\]

At maximum height, the vertical velocity becomes zero. Using the kinematic equation:
\[
v_y^2 =

A golfer hits a ball from ground level on a horizontal surface. The initial velocity of the ball is 21 m/s at an angle of 60° above the horizontal. Assume that the ball is a particle and that no resistance forces act on the ball. Find (a) the maximum height of the ball, (b) the range of the ball, and (c) the speed of the ball at its maximum height.

This physics problem involves calculating the maximum height, range, and speed of a golf ball hit at an angle of 60° with an initial velocity of 21 m/s. It covers key concepts in projectile motion, including vertical and horizontal velocity components, and uses kinematic equations to determine the desired values.

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