To solve this problem, let's define some variables and use the given information step-by-step:

1. Define Variables:

   • Let $x$ be the number of articles of type A in the first lot.
   • Let $y$ be the number of articles of type B in the first lot.
   • The cost price per article for both A and B is the same. Let this be $C$.

2. Relate the Number of Articles in the Lots:

   • The second lot has 50% more articles than the first lot, so the total number of articles in the second lot is $1.5(x + y)$.
   • It’s also given that the number of articles of A in the first lot ($x$) is equal to the number of articles of B in the second lot.

3. Calculate Selling Prices:

   • Since the cost price per article for both A and B is $C$:
     • Selling price of each article of type B is $0.95C$ (since it is sold at a 5% loss).
     • Let the selling price of each article of type A be $S_A$, which we need to find to determine the profit on A.

4. Total Cost Price and Total Selling Price:

   • Total Cost Price (TCP) for both lots: $\text{TCP} = (x + y)C + \left(x + 1.5y\right)C = \left(2x + 2.5y\right)C$

   • Total Selling Price (TSP):

     • Selling price for type B is $y \times 0.95C$ (from the first lot) and $1.5y \times 0.95C$ (from the second lot): $\text{TSP for B} = (y + 1.5y) \times 0.95C = 2.5y \times 0.95C = 2.375yC$
     • Selling price for type A is $x \times S_A + x \times S_A = 2xS_A$.

   • Therefore, the total selling price is: $\text{TSP} = 2xS_A + 2.375yC$

5. Overall Profit Calculation: