Math Problem Statement
Solution
The question involves calculating probabilities for specific events concerning the roll of two six-sided dice. Here are the steps to compute the probabilities:
Event A: The sum is greater than 7.
- Total possible outcomes when two dice are rolled = 6 * 6 = 36.
- Favorable outcomes for sum > 7 (i.e., sums of 8, 9, 10, 11, 12):
- Sum = 8: (2,6), (3,5), (4,4), (5,3), (6,2) → 5 outcomes.
- Sum = 9: (3,6), (4,5), (5,4), (6,3) → 4 outcomes.
- Sum = 10: (4,6), (5,5), (6,4) → 3 outcomes.
- Sum = 11: (5,6), (6,5) → 2 outcomes.
- Sum = 12: (6,6) → 1 outcome.
- Total favorable outcomes = 5 + 4 + 3 + 2 + 1 = 15.
Event B: The sum is not divisible by 5 and not divisible by 6.
- We already know total possible outcomes = 36.
- Sums from two dice that are divisible by 5 or 6:
- Divisible by 5: 5, 10, 15, 20 → (5 is not possible, 15 and 20 are not possible with two dice, only 10 is valid: (4,6), (5,5), (6,4) → 3 outcomes).
- Divisible by 6: 6, 12, 18 → (6: (1,5), (2,4), (3,3), (4,2), (5,1), 12: (6,6) → 7 outcomes).
- Total for divisible by 5 or 6 = 3 + 7 = 10 outcomes.
- Overlapping outcomes are only (6,4) and (4,6) from sum = 10, counted once in the divisible by 5 set.
- Corrected count = 10 - 1 = 9.
- Outcomes not divisible by either 5 or 6 = 36 - 9 = 27.
Now we can calculate the probabilities:
- Probability of Event A (P(A)) = Favorable outcomes for A / Total possible outcomes = 15 / 36.
- Probability of Event B (P(B)) = Outcomes not divisible by either 5 or 6 / Total possible outcomes = 27 / 36.
Let's compute these probabilities and round to two decimal places as requested.The probabilities for the events given are:
- (The sum is greater than 7): 0.42
- (The sum is not divisible by 5 and not divisible by 6): 0.75
Would you like to delve into any details or have any other questions on this?
Here are some related questions you might find interesting:
- How would the probabilities change if the dice were not fair?
- What is the probability of rolling a sum less than 7?
- Can you calculate the probability of rolling an even number sum?
- What are the chances of rolling a sum divisible by 3?
- How do these probabilities translate to practical scenarios like games involving dice?
Tip:
Remember, in probability, knowing the total number of outcomes and how to categorize events based on those outcomes is crucial to determining the likelihood of any event.
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Math Problem Analysis
Mathematical Concepts
Probability
Combinatorics
Formulas
Probability of an event = (Favorable outcomes) / (Total outcomes)
Total outcomes for two dice = 6 * 6 = 36
Theorems
Basic Probability Theorem
Suitable Grade Level
Grades 9-12
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