In this context:

1. The event of "selecting a store with a pharmacy, a floral shop, and a deli" is called the intersection of three events or joint occurrence of these three departments.

2. To determine the probability of selecting a store that does not have all three departments, we can use the given probability information directly.

Since 10% of the stores have all three departments, the probability of selecting a store with all three departments is: $P(\text{Pharmacy} \cap \text{Floral} \cap \text{Deli}) = 0.10$

Therefore, the probability of selecting a store that does not have all three departments is the complement of this probability: $P(\text{not all three departments}) = 1 - P(\text{all three departments}) = 1 - 0.10 = 0.90$

Answer Summary:

1. The name for the event of selecting a store with a pharmacy, floral shop, and deli is the intersection of three events.
2. The probability of selecting a store that does not have all three departments is 0.90 (or 90%).

Would you like more details on the solution or clarification? Here are some related questions to expand understanding:

1. What is the probability of selecting a store that has at least one of these departments?
2. How would you calculate the probability of a store having only two of the three departments?
3. Can you verify the information given using a Venn diagram or inclusion-exclusion principle?
4. How do you interpret joint probabilities in survey data?
5. What would change in calculations if the survey included more departments?

Tip: For multi-category probability problems, drawing a Venn diagram helps visualize overlaps and interactions.