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Let's solve the problem where you need to find the probability of spinning red on the first spin and cyan on the second spin.

The spinner has six sections: 3 red, 2 blue, and 1 cyan.

### Steps:

1. **Probability of spinning red on the first spin**:  
   The number of red sections is 3 out of 6 total sections.  
   Probability = \( \frac{3}{6} = \frac{1}{2} \).

2. **Probability of spinning cyan on the second spin**:  
   The number of cyan sections is 1 out of 6 total sections.  
   Probability = \( \frac{1}{6} \).

3. **Combined probability**:  
   Since both events are independent, you multiply their probabilities:  
   \( \frac{1}{2} \times \frac{1}{6} = \frac{1}{12} \).

The probability of spinning red on the first spin and cyan on the second spin is \( \frac{1}{12} \).

Would you like more details on this, or have any further questions? Here are some related questions you can explore:

1. What is the probability of spinning blue on both spins?
2. What is the probability of spinning cyan on the first spin and red on the second?
3. What is the probability of not spinning cyan on both spins?
4. What is the probability of spinning red on either the first or second spin?
5. What is the probability of spinning blue on exactly one of the spins?

**Tip**: In probability problems involving multiple events, always check if the events are independent or dependent to determine the correct approach.

Find the probability of spinning red on the first spin and cyan on the second spin using a spinner with six sections (3 red, 2 blue, and 1 cyan).

Learn how to calculate the probability of spinning red on the first spin and cyan on the second spin using a spinner with six equal sections. This problem covers key probability concepts and is suitable for students in Grades 6-8.

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