Math Problem Statement

Consider all four-digit numbers that can be made from the digits 0-7 (assume that numbers cannot start with 0 ). What is the probability of choosing a random number from this group that is less than or equal to 5000 ? Enter a fraction or round your answer to 4 decimal places, if necessary.

Solution

We are tasked with finding the probability of selecting a four-digit number made from the digits 0-7 that is less than or equal to 5000. The four-digit numbers cannot start with 0.

Step 1: Total possible four-digit numbers

The digits can be chosen from the set {0, 1, 2, 3, 4, 5, 6, 7}. The first digit cannot be 0, leaving 7 choices (1 through 7) for the first digit. For each of the remaining three digits, there are 8 possible choices (0 through 7).

Thus, the total number of possible four-digit numbers is: 7×8×8×8=7×83=7×512=35847 \times 8 \times 8 \times 8 = 7 \times 8^3 = 7 \times 512 = 3584

Step 2: Numbers less than or equal to 5000

For a number to be less than or equal to 5000, the first digit must be one of 1, 2, 3, 4, or 5 (since it cannot start with 0). We have 5 choices for the first digit. The remaining three digits can be any of the 8 digits.

Thus, the number of four-digit numbers less than or equal to 5000 is: 5×8×8×8=5×512=25605 \times 8 \times 8 \times 8 = 5 \times 512 = 2560

Step 3: Probability calculation

The probability is the ratio of the favorable outcomes (numbers less than or equal to 5000) to the total possible outcomes. Therefore, the probability is: Probability=25603584\text{Probability} = \frac{2560}{3584}

We can simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 512: 25603584=57\frac{2560}{3584} = \frac{5}{7}

Thus, the probability is 57\frac{5}{7}.

Final Answer:

The probability of selecting a number less than or equal to 5000 is 57\frac{5}{7}, or approximately 0.7143 when rounded to four decimal places.


Would you like more details, or do you have any questions?

Here are some related questions you might find interesting:

  1. What if the digits were chosen from the set {0-9} instead of {0-7}?
  2. How would the probability change if the number had to be strictly less than 4000?
  3. What if the number had to be divisible by 3?
  4. How many of these numbers are prime?
  5. How does the probability change if repetition of digits is not allowed?

Tip: When simplifying probabilities, always check if the numerator and denominator have a common factor!

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Math Problem Analysis

Mathematical Concepts

Probability
Combinatorics
Number Theory

Formulas

Total four-digit numbers = 7 * 8^3 = 3584
Numbers <= 5000 = 5 * 8^3 = 2560
Probability = Favorable outcomes / Total outcomes

Theorems

Basic Probability Theorem

Suitable Grade Level

Grades 8-10