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The problem asks to find the probability of rolling either an even number or a number less than 3 on a six-sided die. The sides of the die are numbered 1 through 6.

### Step 1: List the outcomes for each condition.
- **Even numbers**: These are 2, 4, and 6.
- **Numbers less than 3**: These are 1 and 2.

### Step 2: Combine the outcomes.
We need the probability of rolling an even number **or** a number less than 3. However, we should be careful not to double-count any numbers that meet both conditions. In this case, **2** is both even and less than 3, so we count it only once.

Thus, the distinct outcomes are:
- 1 (less than 3)
- 2 (both even and less than 3)
- 4 (even)
- 6 (even)

So, the favorable outcomes are: **1, 2, 4, 6**.

### Step 3: Calculate the probability.
There are 4 favorable outcomes (1, 2, 4, 6) out of 6 possible outcomes (since the die has 6 sides).

Thus, the probability is:
\[
P = \frac{4}{6} = \frac{2}{3}
\]

### Final Answer:
The probability is \( \frac{2}{3} \).

Would you like more details or have any other questions? Here are some related questions for further exploration:

1. What is the probability of rolling an odd number on a six-sided die?
2. How does the probability change if we use an eight-sided die instead?
3. What is the probability of rolling a number greater than 4 or an even number?
4. Can you calculate the probability of rolling a number that is both even and less than 3?
5. What is the probability of rolling a prime number on a six-sided die?

**Tip:** When calculating probabilities involving "or" conditions, remember to exclude any overlapping outcomes to avoid double-counting.

A single, six-sided die is rolled. Find the probability of rolling an even number or a number less than 3.

Learn how to calculate the probability of rolling either an even number or a number less than 3 on a six-sided die. This problem involves the addition rule for probability, highlighting how to avoid double-counting overlapping outcomes. Suitable for students in Grades 6-8.

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