Let's analyze the image. It shows a question about finding probabilities with a standard 6-sided die. Here's a breakdown of each part of the problem:

1. The number showing is a 3:

• A standard die has 6 faces: 1, 2, 3, 4, 5, 6.
• The probability of rolling a 3 is the number of favorable outcomes (1 outcome: rolling a 3) divided by the total number of outcomes (6 sides).

$P(\text{rolling a 3}) = \frac{1}{6}$

2. The number showing is an even number:

• The even numbers on a die are 2, 4, and 6. So, there are 3 favorable outcomes (2, 4, 6).

$P(\text{even number}) = \frac{3}{6} = \frac{1}{2}$

3. The number showing is greater than 4:

• The numbers greater than 4 are 5 and 6, so there are 2 favorable outcomes (5, 6).

$P(\text{number greater than 4}) = \frac{2}{6} = \frac{1}{3}$

Summary of Answers:

1. Probability of rolling a 3: $\frac{1}{6}$
2. Probability of rolling an even number: $\frac{1}{2}$
3. Probability of rolling a number greater than 4: $\frac{1}{3}$

Do you have any questions or would you like more details on these probabilities?

Here are 5 related questions to practice:

1. What is the probability of rolling a number less than 3?
2. If two dice are rolled, what is the probability that both show a 3?
3. What is the probability of rolling an odd number on a standard die?
4. What is the probability of rolling a prime number on a standard die?
5. If the die is rolled twice, what is the probability that the second roll is greater than the first?

Tip: For any event involving a standard die, always divide the favorable outcomes by the total number of sides (which is 6).