To solve this, we calculate the probability of each independent event happening and then multiply the probabilities because the events are independent.

1. Probability of getting a 6 on the first roll:
   A standard number cube (die) has six faces numbered 1 to 6. The probability of rolling a 6 is:
   $P(\text{6 on first roll}) = \frac{1}{6}$

2. Probability of getting a number less than 5 on the second roll:
   The numbers less than 5 are 1, 2, 3, and 4. There are 4 favorable outcomes out of 6 total outcomes. So, the probability is:
   $P(\text{number less than 5 on second roll}) = \frac{4}{6} = \frac{2}{3}$

3. Combined probability:
   Since the events are independent, we multiply the probabilities:
   $P(\text{6 on first roll and number less than 5 on second roll}) = \frac{1}{6} \times \frac{2}{3} = \frac{2}{18} = \frac{1}{9}$

Final Answer:

The probability of rolling a 6 on the first roll and a number less than 5 on the second roll is:
$\boxed{\frac{1}{9}}$

Would you like to see a step-by-step breakdown of how probabilities for independent events are calculated or related concepts?

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Related Questions:

1. What is the probability of rolling two 6s in two rolls of a number cube?
2. How many outcomes are there if a die is rolled three times?
3. What is the probability of rolling an even number on both rolls?
4. If a number cube is rolled twice, what is the probability of the sum being 7?
5. How does the probability change if the die is not fair?

Tip: When dealing with independent events, always multiply the probabilities of each event to find the overall probability.