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The problem describes a parking lot with 200 cars, where 50 are white, 30 are red, and 20 are silver. The total number of cars that are white, red, or silver is:

\[
50 + 30 + 20 = 100 \text{ cars.}
\]

This means that the remaining \( 200 - 100 = 100 \) cars are of some other color, but none are green, since the question implies that no car in the parking lot is green.

The probability of selecting a green car from the parking lot is therefore \( 0 \), because there are no green cars. So the correct answer is:

\[
\boxed{A. 0}
\]

This is the probability that *must* be true, while the other options (0.1, 0.2, 0.6) are not possible for green cars since there are no green cars in the lot.

Would you like more details or have any questions?

Here are 5 related questions to expand on this:
1. How do you calculate the probability of selecting a car of a certain color?
2. If the number of red cars was doubled, how would that affect the probability of choosing a red car?
3. What is the probability of selecting either a white, red, or silver car?
4. How would the problem change if green cars were added to the parking lot?
5. What is the sum of probabilities for all possible colors in the parking lot?

**Tip**: Always ensure the total probability of all outcomes equals 1 when dealing with complete probability scenarios.

In a parking lot with 200 cars, 50 cars are white, 30 cars are red, and 20 cars are silver. One car will be selected at random from the parking lot. If each car in the parking lot is of a single color, which of the following cannot be the probability that the selected car will be green? A. 0 B. 0.1 C. 0.2 D. 0.6

Explore how to solve a probability question involving a parking lot with 200 cars. Learn to calculate the probability of selecting a green car, given that no green cars are present. This problem is ideal for students in Grades 6-8, covering basic probability concepts and formulas.

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