Math Problem Statement
You pick a coin at random from the set shown at the right, and then pick a second coin without replacing the first. Find the probability. P(quarter then nickel)
Solution
To calculate the probability of picking a quarter first and then a nickel without replacement, we need to follow these steps:
- Determine the total number of coins in the set.
- Calculate the probability of selecting a quarter in the first draw.
- Calculate the probability of selecting a nickel in the second draw, given that a quarter has already been removed.
- Multiply the probabilities from steps 2 and 3, as these are dependent events.
Let the number of quarters = , nickels = , and total coins = . Without specific numbers, we solve symbolically:
Step-by-step Formula
-
First draw: Probability of selecting a quarter:
-
Second draw (after a quarter is removed):
-
Multiply these probabilities:
Example Calculation
If the set contains, for instance:
- 3 quarters (),
- 2 nickels (),
- Total coins (),
Then:
-
Probability of selecting a quarter first:
-
Probability of selecting a nickel second:
-
Combined probability:
Let me know the exact number of coins if you'd like a specific solution!
Would you like a detailed breakdown or have any questions?
Here are 5 related questions:
- What is the probability of picking two quarters in a row without replacement?
- How does the probability change if the first coin is replaced before the second draw?
- What is the probability of selecting a nickel first and then a quarter?
- How can you determine probabilities for more than two consecutive picks?
- What happens if the set contains different types of coins, like dimes or pennies?
Tip: When dealing with "without replacement" problems, always adjust the total count of items after each selection.
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Math Problem Analysis
Mathematical Concepts
Probability
Conditional Probability
Dependent Events
Formulas
P(quarter) = Q / T
P(nickel | quarter picked) = N / (T - 1)
P(quarter then nickel) = (Q / T) * (N / (T - 1))
Theorems
Multiplication Rule for Dependent Events
Suitable Grade Level
Grades 7-9
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