Math Problem Statement

You pick a coin at random from the set shown at the​ right, and then pick a second coin without replacing the first. Find the probability. ​P(quarter then nickel​)

Solution

To calculate the probability of picking a quarter first and then a nickel without replacement, we need to follow these steps:

  1. Determine the total number of coins in the set.
  2. Calculate the probability of selecting a quarter in the first draw.
  3. Calculate the probability of selecting a nickel in the second draw, given that a quarter has already been removed.
  4. Multiply the probabilities from steps 2 and 3, as these are dependent events.

Let the number of quarters = QQ, nickels = NN, and total coins = TT. Without specific numbers, we solve symbolically:

Step-by-step Formula

  1. First draw: Probability of selecting a quarter: P(quarter)=QTP(\text{quarter}) = \frac{Q}{T}

  2. Second draw (after a quarter is removed): P(nickel | quarter picked)=NT1P(\text{nickel | quarter picked}) = \frac{N}{T-1}

  3. Multiply these probabilities: P(quarter then nickel)=P(quarter)P(nickel | quarter picked)=QTNT1P(\text{quarter then nickel}) = P(\text{quarter}) \cdot P(\text{nickel | quarter picked}) = \frac{Q}{T} \cdot \frac{N}{T-1}

Example Calculation

If the set contains, for instance:

  • 3 quarters (Q=3Q = 3),
  • 2 nickels (N=2N = 2),
  • Total coins (T=3+2=5T = 3 + 2 = 5),

Then:

  1. Probability of selecting a quarter first: P(quarter)=35P(\text{quarter}) = \frac{3}{5}

  2. Probability of selecting a nickel second: P(nickel | quarter picked)=24=12P(\text{nickel | quarter picked}) = \frac{2}{4} = \frac{1}{2}

  3. Combined probability: P(quarter then nickel)=3512=310P(\text{quarter then nickel}) = \frac{3}{5} \cdot \frac{1}{2} = \frac{3}{10}

Let me know the exact number of coins if you'd like a specific solution!


Would you like a detailed breakdown or have any questions?

Here are 5 related questions:

  1. What is the probability of picking two quarters in a row without replacement?
  2. How does the probability change if the first coin is replaced before the second draw?
  3. What is the probability of selecting a nickel first and then a quarter?
  4. How can you determine probabilities for more than two consecutive picks?
  5. What happens if the set contains different types of coins, like dimes or pennies?

Tip: When dealing with "without replacement" problems, always adjust the total count of items after each selection.

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Math Problem Analysis

Mathematical Concepts

Probability
Conditional Probability
Dependent Events

Formulas

P(quarter) = Q / T
P(nickel | quarter picked) = N / (T - 1)
P(quarter then nickel) = (Q / T) * (N / (T - 1))

Theorems

Multiplication Rule for Dependent Events

Suitable Grade Level

Grades 7-9