Math Problem Statement

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following:

5 Pennies 28 Dimes 17 Nickels 29 Quarters

What is the probability that you reach into the jar and randomly grab a quarter and then, without replacement, a nickel? Express your answer as a fraction or a decimal number rounded to four decimal places.

Solution

We can solve this problem using the concept of conditional probability because you're selecting coins without replacement. Let's break it down:

Step 1: Determine the total number of coins in the jar

You have:

  • 5 pennies
  • 28 dimes
  • 17 nickels
  • 29 quarters

So, the total number of coins is:

5+28+17+29=795 + 28 + 17 + 29 = 79

Step 2: Probability of selecting a quarter first

The probability of selecting a quarter on the first draw is the number of quarters divided by the total number of coins:

P(quarter first)=2979P(\text{quarter first}) = \frac{29}{79}

Step 3: Probability of selecting a nickel second

After you select a quarter, you don't replace it, so there are now 78 coins left in the jar. The number of nickels remains 17. Thus, the probability of selecting a nickel after having already selected a quarter is:

P(nickel second | quarter first)=1778P(\text{nickel second | quarter first}) = \frac{17}{78}

Step 4: Multiply the probabilities

Since these events are sequential and without replacement, the overall probability is the product of these two probabilities:

P(quarter and then nickel)=2979×1778P(\text{quarter and then nickel}) = \frac{29}{79} \times \frac{17}{78}

Let's calculate this:

P(quarter and then nickel)=29×1779×78=49361620.07998P(\text{quarter and then nickel}) = \frac{29 \times 17}{79 \times 78} = \frac{493}{6162} \approx 0.07998

Final Answer:

The probability that you grab a quarter first and then a nickel is approximately 0.0800 (rounded to four decimal places).

Do you want further details or have any questions?

Here are 5 related questions to expand on the topic:

  1. What is the probability of grabbing a penny and then a dime without replacement?
  2. How would the probability change if the coins were replaced after each selection?
  3. What is the probability of grabbing two quarters in a row without replacement?
  4. What is the probability of selecting two coins of the same type in a row (e.g., two dimes)?
  5. How would the total probability change if the jar also contained 10 half-dollars?

Tip: Always be careful with "without replacement" problems, as the total number of objects decreases after each selection, changing the probabilities.

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Math Problem Analysis

Mathematical Concepts

Probability
Conditional Probability
Without Replacement

Formulas

Total Probability: P(A and B) = P(A) * P(B | A)
P(quarter first) = 29/79
P(nickel second | quarter first) = 17/78

Theorems

Multiplication Rule of Probability
Conditional Probability

Suitable Grade Level

Grades 8-10