Math Problem Statement
Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following:
5 Pennies 28 Dimes 17 Nickels 29 Quarters
What is the probability that you reach into the jar and randomly grab a quarter and then, without replacement, a nickel? Express your answer as a fraction or a decimal number rounded to four decimal places.
Solution
We can solve this problem using the concept of conditional probability because you're selecting coins without replacement. Let's break it down:
Step 1: Determine the total number of coins in the jar
You have:
- 5 pennies
- 28 dimes
- 17 nickels
- 29 quarters
So, the total number of coins is:
Step 2: Probability of selecting a quarter first
The probability of selecting a quarter on the first draw is the number of quarters divided by the total number of coins:
Step 3: Probability of selecting a nickel second
After you select a quarter, you don't replace it, so there are now 78 coins left in the jar. The number of nickels remains 17. Thus, the probability of selecting a nickel after having already selected a quarter is:
Step 4: Multiply the probabilities
Since these events are sequential and without replacement, the overall probability is the product of these two probabilities:
Let's calculate this:
Final Answer:
The probability that you grab a quarter first and then a nickel is approximately 0.0800 (rounded to four decimal places).
Do you want further details or have any questions?
Here are 5 related questions to expand on the topic:
- What is the probability of grabbing a penny and then a dime without replacement?
- How would the probability change if the coins were replaced after each selection?
- What is the probability of grabbing two quarters in a row without replacement?
- What is the probability of selecting two coins of the same type in a row (e.g., two dimes)?
- How would the total probability change if the jar also contained 10 half-dollars?
Tip: Always be careful with "without replacement" problems, as the total number of objects decreases after each selection, changing the probabilities.
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Math Problem Analysis
Mathematical Concepts
Probability
Conditional Probability
Without Replacement
Formulas
Total Probability: P(A and B) = P(A) * P(B | A)
P(quarter first) = 29/79
P(nickel second | quarter first) = 17/78
Theorems
Multiplication Rule of Probability
Conditional Probability
Suitable Grade Level
Grades 8-10
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