Math Problem Statement

What is the probability that a point randomly chosen in the large triangle is also in Region A? A coordinate grid with a right triangular region shown. The x-axis extends from 0 to 15. The y-axis extends from 0 to 11. The vertices of the right triangle are the points begin ordered pair 0 comma 0 end ordered pair comma begin ordered pair 12 comma 0 end ordered pair comma begin ordered pair 0 comma 8 end ordered pair. A vertical line segment divides the right triangle into two smaller regions, labeled A and B. The endpoints of this line segment are begin ordered pair 3 comma 0 end ordered pair and begin ordered pair 3 comma 6 end ordered pair. Region A is to the left of the dividing line segment and is a trapezoid. Region B is to the right of the dividing line segment and is a right triangle. Responses about 22% about 22% about 33% about 33% about 44% about 44% about 88%

Solution

To solve the problem, we need to calculate the area of Region A as a fraction of the area of the large triangle, and use that fraction as the probability. Here's the step-by-step breakdown:


Step 1: Area of the Large Triangle

The vertices of the triangle are (0,0)(0, 0), (12,0)(12, 0), and (0,8)(0, 8). The area of a triangle is given by: Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} Here, the base is 12 (distance along the x-axis), and the height is 8 (distance along the y-axis). Thus: Area of large triangle=12×12×8=48\text{Area of large triangle} = \frac{1}{2} \times 12 \times 8 = 48


Step 2: Description of Region A

Region A is a trapezoid, bounded by:

  1. The y-axis (x=0x = 0),
  2. The vertical line x=3x = 3,
  3. The hypotenuse of the large triangle (sloping line from (12,0)(12, 0) to (0,8)(0, 8)),
  4. The horizontal line y=6y = 6.

Trapezoid Dimensions

The key to finding the area of Region A is calculating the lengths of the two parallel sides (heights of the trapezoid):

  • The vertical line x=0x = 0 extends from y=0y = 0 to y=8y = 8, so one height is 8.
  • The vertical line x=3x = 3 extends from y=0y = 0 to y=6y = 6, so the other height is 6.

The width of the trapezoid (the distance between x=0x = 0 and x=3x = 3) is 3.


Step 3: Area of Region A

The area of a trapezoid is given by: Area=12×(base1+base2)×height\text{Area} = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height} Here, base1=8\text{base}_1 = 8, base2=6\text{base}_2 = 6, and height=3\text{height} = 3. Thus: Area of Region A=12×(8+6)×3=12×14×3=21\text{Area of Region A} = \frac{1}{2} \times (8 + 6) \times 3 = \frac{1}{2} \times 14 \times 3 = 21


Step 4: Probability

The probability is the ratio of the area of Region A to the area of the large triangle: Probability=Area of Region AArea of Large Triangle=2148\text{Probability} = \frac{\text{Area of Region A}}{\text{Area of Large Triangle}} = \frac{21}{48} Simplify: Probability=7160.4375 or 43.75%\text{Probability} = \frac{7}{16} \approx 0.4375 \text{ or } 43.75\%


Final Answer

The probability is approximately 44%.


Follow-up Questions

  1. How do we calculate the area of Region B to confirm the result?
  2. What would the probability be if Region A was divided further into smaller sections?
  3. How does the slope of the hypotenuse affect the division of regions?
  4. Can we confirm the dimensions of Region A using algebraic methods?
  5. How does the probability change if the dividing line shifts horizontally?

Tip: Always verify your trapezoid dimensions carefully, as small errors can significantly impact area calculations.

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Math Problem Analysis

Mathematical Concepts

Probability
Geometry
Area of Triangles
Area of Trapezoids

Formulas

Area of a triangle: (1/2) × base × height
Area of a trapezoid: (1/2) × (base1 + base2) × height
Probability = Area of Region A / Area of Large Triangle

Theorems

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Suitable Grade Level

Grades 8-10