Math Problem Statement

What is the probability of being dealt a pair of aces in a five-card hand?

Solution

The question asks for determining the type of probability method (theoretical, relative frequency, or subjective) to answer:

33. What is the probability of being dealt a pair of aces in a five-card hand?


Answer

The appropriate method to use here is theoretical probability, because:

  1. The probability can be calculated based on mathematical reasoning and combinatorics without requiring experimentation or personal opinion.
  2. It relies on the assumption that all outcomes (five-card hands) are equally likely and can be determined by calculating combinations of card arrangements.

Example of Theoretical Probability Calculation (Optional):

To find the exact probability:

  1. Total ways to choose 5 cards from 52: (525)\binom{52}{5}
  2. Total ways to form a pair of aces: (42)\binom{4}{2} (choose 2 aces from the 4 available) and (483)\binom{48}{3} (choose 3 non-aces from the remaining 48 cards).
  3. Probability: P=(42)(483)(525)P = \frac{\binom{4}{2} \cdot \binom{48}{3}}{\binom{52}{5}}

Let me know if you’d like to work through the full calculation.


Do you want further clarification or have any questions?

Below are 5 related questions to expand your understanding:

  1. How do you calculate theoretical probability using combinatorics?
  2. What distinguishes theoretical probability from relative frequency?
  3. Could relative frequency ever be used to approximate this scenario?
  4. How would subjective probability apply in cases where no mathematical model is available?
  5. Can theoretical probability always guarantee exact results in card games?

Tip: Theoretical probability is often used when you can logically determine all possible outcomes, like in card games or dice rolls. Always check if assumptions like "equal likelihood" hold!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Probability
Combinatorics

Formulas

Total combinations formula: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
Probability formula: \( P = \frac{\text{Favorable Outcomes}}{\text{Total Outcomes}} \)

Theorems

-

Suitable Grade Level

Grades 9-12