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The problem asks for the probability of rolling either a "1" or a "2" on a special 46-sided die.

In a single roll of a 46-sided die, each side has an equal probability of appearing. The probability of any specific outcome is calculated as:

\[
P(\text{specific outcome}) = \frac{1}{46}
\]

The problem involves rolling a "1" **or** a "2." Since these are two distinct outcomes, we add their probabilities. The probability of rolling a "1" is \(\frac{1}{46}\), and the probability of rolling a "2" is also \(\frac{1}{46}\).

Thus, the probability of rolling a "1" or a "2" is:

\[
P(1 \text{ or } 2) = P(1) + P(2) = \frac{1}{46} + \frac{1}{46} = \frac{2}{46} = \frac{1}{23}
\]

So, the probability of rolling a "1" or a "2" is **\(\frac{1}{23}\)**.

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### Related Questions:
1. What is the probability of rolling a number greater than 40 on this die?
2. What is the probability of rolling an odd number on this 46-sided die?
3. If you roll the die twice, what is the probability of getting two "1"s?
4. How many outcomes would result in rolling a prime number on this die?
5. What is the probability of rolling any number greater than 10 but less than 30?

### Tip:
In probability, the keyword "or" typically means you add probabilities of distinct, mutually exclusive events.

Suppose you roll a special 46-sided die. What is the probability that the number rolled is a '1' OR a '2'?

Learn how to calculate the probability of rolling a '1' or '2' on a special 46-sided die. Using basic probability concepts and mutually exclusive event rules, the solution involves adding the probabilities for each outcome. This problem is suitable for students in Grades 6-8.

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