To find the probability of rolling a 3 or a 4 on a six-sided die, follow these steps:

1. There are 6 sides on a die, each equally likely.
2. The numbers 3 and 4 are two possible outcomes.
3. The probability of rolling a specific number is $\frac{1}{6}$.
4. Since the die has two favorable outcomes (3 and 4), the combined probability is: $P(\text{3 or 4}) = P(3) + P(4) = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}.$

So, the probability of throwing a 3 or a 4 is $\frac{1}{3}$.

Would you like more details on probability calculations?

Here are 5 related questions:

1. What is the probability of rolling an even number on a six-sided die?
2. What is the probability of rolling a number less than 5 on a six-sided die?
3. What is the probability of rolling a 2 or a 6 on a six-sided die?
4. What is the probability of rolling a number greater than 4?
5. How would the probability change if the die were biased?

Tip: To calculate probabilities, remember that for mutually exclusive events, you add their probabilities.